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Maru [420]
2 years ago
12

Wells College in Aurora, New York was previously an all-girls college. In 2005, the college began to allow boys to enroll. By 20

12, the ratio of boys to girls was 3 to 7. If there were 200 more girls than boys in2012, how many boys were enrolled that year?
Mathematics
1 answer:
vagabundo [1.1K]2 years ago
5 0

Answer:

150 boys were enrolled in 2012

Step-by-step explanation:

Let the number of boys enrolled in 2012 be x

Let the number of girls enrolled in 2012 be x + 200

Ratio of boys to girls in 2012 enrollment = 3/7

Now;

3/7 = x/x + 200

7x = 3(x + 200)

7x = 3x + 600

7x - 3x = 600

4x = 600

x = 600/4

x = 150 boys

Hence, 150 boys were enrolled in 2012

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3 years ago
AC=(5x+12) and BD =8x? Can somebody help me to slove it
AleksAgata [21]
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3 years ago
I am a multiple of 3 and 5. the sum of my digits is 9. what number am I?
iVinArrow [24]

Answer:

The answer is 45.

Step-by-step explanation:

This number is a multiple of 3 and 5, since it is divisible by both of these numbers.

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3 0
3 years ago
33. A competition question requests students to form a three-digit number.
aniked [119]

Answer:

  532

Step-by-step explanation:

  532 = 2·2·7·19

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There are 24 possible 3-digit numbers from the set {2, 3, 5, 7}. Of those, 6 have four factors: 372, 375, 532, 572, 732, 735.

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7 0
3 years ago
Explain how you got the answer
Gnoma [55]

Answer:

\huge\boxed{Center = (3,3),Radius = 2\sqrt{15} }

Step-by-step explanation:

<u><em>Given equation is</em></u>

x^2 + y^2 -6x-6y -42 = 0

Adding 42 to both sides

x^2 + y^2 -6x-6y = 42\\

Completing squares

x^2 -6x+y^2 -6x = 42\\(x)^2 - 2(x)(3) +y^2 - 2(y)(3) = 42

Adding (3)² => 9 and (3)² => 9 to both sides

(x-3)^2+(y-3)^2 = 42+9+9\\(x-3)^2 + (y-3)^2 = 60\\(x-3)^2  (y-3)^2 = (2{\sqrt{15})^2}

Comparing it with (x-h)^2+(y-k)^2 = r^2 where Center = (h,k) and Radius = r

We get:

Center = (3,3)

Radius = 2\sqrt{15}

7 0
3 years ago
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