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irina [24]
3 years ago
13

Tricia made a circular mat from a square piece of cloth as shown in the diagram below.

Mathematics
1 answer:
kap26 [50]3 years ago
8 0

The option C) 49 inches is the circumference of the circular mat.

<u>Step-by-step explanation:</u>

  • Tricia made a circular mat from a square piece of cloth.
  • The measure of the side length of the square = 14 inches.
  • The length of the side is same as the diameter of the circle.
  • Therefore, the diameter of the circular mat = 14 inches.

<u>To find radius :</u>

Radius = diameter / 2

⇒ 14/2

⇒ 7 inches.

<u>To find the circumference of the circular mat :</u>

Circumference = 2πr

where,

π has the default value of 3.14

r is the radius of the circular mat.

⇒ 2 × 3.14 × 7

⇒ 44 inches.

∴ The circumference of the circular mat is 44 inches.

Since, it is not given in the option. The option C) 49 inches which is close to 44 inches is the right option.

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f(x)=13|x-5|-6 is the equation represented by all the operations.

<u>Step-by-step explanation:</u>

The given function is

f(x)=|x|

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f(x)=13|x|

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It shifted right by 5 units then the function becomes,

f(x)=13|x-5|-6

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Step-by-step explanation:

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Answer:

The solution is given below;

Step-by-step explanation:

The computation is shown below:

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A food processor packages orange juice in small jars. The weights of the filled jars are approximately normally distributed with
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Answer:

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And we can find this probability using the complement rule and with excel or the normal standard table:

P(z>1.61)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(10.5,0.3)  

Where \mu=10.5 and \sigma=0.3

We are interested on this probability

P(X>10.983)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>10.983)=P(\frac{X-\mu}{\sigma}>\frac{10.983-\mu}{\sigma})=P(Z>\frac{10.983-10.5}{0.3})=P(z>1.61)

And we can find this probability using the complement rule and with excel or the normal standard table:

P(z>1.61)=1-P(z

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