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DochEvi [55]
3 years ago
12

Two ice skaters stand at rest in the center of an ice rink. When they push off against one another the 62-kg skater acquires a s

peed of 0.70 m/s. If the speed of the other skater is 0.90 m/s, what is this skater's mass?
Physics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

48.22 kg

Explanation:

Applying the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

Note:  Since both skaters were initially at rest, then their total momentum  before collision is equal to zero.

And the velocity of the second skater will be in opposite direction to the first.

0 = mv+m'v'.................... Equation 1

Where m = mass of the first skater, m' = mass of the second skater, v = final velocity of the first skater, v' = final velocity of the second skater.

make v' the subject of the equation

m' = -mv/v'................. Equation 2

Given: m = 62 kg, v = 0.7 m/s, v' = -0.9 m/s (opposite direction to the first)

Substitute into equation 1

m' = -62(0.7)/-0.9

m' = 48.22 kg

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We can find the acceleration as follows:

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Answer:

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1 year ago
You put a 3 kg block in the box, so the total mass is now 8 kg, and you launch this heavier box with an initial speed of 4 m/s.
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Answer:

0.7 secs

Explanation:

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Δ<em>t=Δ∨x/χgμ............................equ 1</em>

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<em>Δvx=vf-vt</em>

Δvx=0-4m/s

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Now substitute the various values in equ 1

Δ<em>t=Δ∨x/χgμ</em>

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3 years ago
Read 2 more answers
Two spherical objects at the same altitude move with identical velocities and experience the same drag force at a time t. If Obj
Anna35 [415]

Answer:

<em>The object with the twice the area of the other object, will have the larger drag coefficient.</em>

<em></em>

Explanation:

The equation for drag force is given as

F_{D} = \frac{1}{2}pu^{2}  C_{D} A

where F_{D} IS the drag force on the object

p = density of the fluid through which the object moves

u = relative velocity of the object through the fluid

p = density of the fluid

C_{D} = coefficient of drag

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Note that C_{D} is a dimensionless coefficient related to the object's geometry and taking into account both skin friction and form drag. The most interesting things is that it is dependent on the linear dimension, which means that it will vary directly with the change in diameter of the fluid

The above equation can also be broken down as

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where P_{D} is the pressure exerted by the fluid on the area A

Also note that P_{D} = \frac{1}{2}pu^{2}

which also clarifies that the drag force is approximately proportional to the abject's area.

<em>In this case, the object with the twice the area of the other object, will have the larger drag coefficient.</em>

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Answer:

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