We can find the acceleration as follows:

Answer:
D. 2 m/s^2
Answer:
0.7 secs
Explanation:
In this question, the speed does not change as the mass changes. So we can use
Δ<em>t=Δ∨x/χgμ............................equ 1</em>
To stop, the final speed will be 0
Therefore,
<em>Δvx=vf-vt</em>
Δvx=0-4m/s
= -4m/s
Now substitute the various values in equ 1
Δ<em>t=Δ∨x/χgμ</em>
Δ<em>t= -</em>4m/s/(9.8m/s∧2) (0.6)
Δ<em>t=</em>0.7 secs
Answer:
<em>The object with the twice the area of the other object, will have the larger drag coefficient.</em>
<em></em>
Explanation:
The equation for drag force is given as

where
IS the drag force on the object
p = density of the fluid through which the object moves
u = relative velocity of the object through the fluid
p = density of the fluid
= coefficient of drag
A = area of the object
Note that
is a dimensionless coefficient related to the object's geometry and taking into account both skin friction and form drag. The most interesting things is that it is dependent on the linear dimension, which means that it will vary directly with the change in diameter of the fluid
The above equation can also be broken down as
∝
A
where
is the pressure exerted by the fluid on the area A
Also note that
= 
which also clarifies that the drag force is approximately proportional to the abject's area.
<em>In this case, the object with the twice the area of the other object, will have the larger drag coefficient.</em>
Answer:
the variables in a study of a cause-and-effect relationship are called the independent and dependent variables. The independent variables is the cause and the dependent variables is the effects. It's value depends on the changes in the independent variable.
Explanation:
I hope this small infor is helpful