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meriva
3 years ago
13

Which best compares and contrasts Banking and Investment Planning?

Physics
1 answer:
valina [46]3 years ago
4 0

Answer:

Its C i think

Explanation:

makes the most sense

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Write your answer to the question below.
ElenaW [278]

Answer:

Hi... Potential energy is converted to kinetic energy and kinetic energy is converted to potential energy

8 0
3 years ago
A 10-meter rope is lying on the floor and has a mass force of 20 N. How much work is required to raise one end of the rope to a
VMariaS [17]
Answer:10N

Explanation: I think
7 0
3 years ago
According to Newton's first law of motion, what would happen to a car traveling at a constant velocity of 55 MPH to the west in
mart [117]

Explanation:

  • Newton's first law of motion says that an object will be at rest or it will be in motion until an unbalanced force acts on it.
  • In this case, a car traveling at a constant velocity of 55 mph to the west in the absence of an unbalanced force.
  • It would mean that the car will continue to move with a constant velocity of 55 mph to the west due to Newton's first law of motion.
6 0
3 years ago
Which of the balls will exert the smallest force on object A?Why
olganol [36]
The 1kg ball would exert the smallest force.

As force = mass x gravity, this means that the smaller the mass (kg), the lesser the force.

When the mass is lighter (1kg):

Force = mass x gravity
Force = 1 x 9.8
Force = 9.8N

Compared to when the mass is heavier (10kg)

Force = mass x gravity
Force = 10 x 9.8
Force = 98N

Where this proves that the lighter the mass, the smaller the force exerted.
6 0
2 years ago
A speeding motorist traveling down a straight highway at 100 km/h passes a parked police car. It takes the police constable 1.0
Lubov Fominskaja [6]

Answer:

t = 7.5 s

Explanation:

The distance traveled by the car at the time of meeting of the two cars must be the same. First, we calculate the distance traveled by the police car. For that we use 2nd equation of motion. Here, we take the time when police car starts to be reference. So,

s₁ = Vi t + (0.5)gt²

where,

s₁ = distance traveled by police car

Vi = Initial Velocity = 0 m/s

t = time taken

Therefore,

s₁ = (0 m/s)(t) + (0.5)(9.8 m/s²)t²

s₁ = 4.9 t²

Now, we calculate the distance traveled by the car. For constant speed and time to be 1 second more than the police car time, due to car starting time, we get:

s₂ = Vt = V(t + 1)

where,

s₂ = distance traveled by car

V = Velocity of car = (100 km/h)(1000 m/1 km)(1 h/ 3600 s) = 27.78 m/s

Therefore,

s₂ = 27.78 t + 27.78

Now, we know that at the time of meeting:

s₁ = s₂

4.9 t² = 27.78 t + 27.78

4.9 t² - 270.78 t - 27.78 = 0

solving the equation and choosing the positive root:

t = 6.5 s

since, we want to know the time from the moment car crossed police car. Therefore, we add 1 second of starting time in this.

t = 6.5 s + 1 s

<u>t = 7.5 s</u>

6 0
3 years ago
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