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julsineya [31]
3 years ago
15

What is the wavelength of a sound wave with a frequency of 770 Hz if it speed is 290 m/s?

Physics
1 answer:
Studentka2010 [4]3 years ago
7 0

The wavelength of sound wave with frequency 770 Hz and speed of 290 m/s is equal to 0.3767 m

<h3>Explanation:</h3>

The wave equation determining the relationship between speed, frequency and wavelength of a sound wave is given by:

<u>Speed of sound = Frequency of sound × Wavelength of sound wave</u>

v = n × λ .................................(1)

Given:

v = Speed of sound wave = 290 m/s

n = Frequency of sound = 770 Hz

λ = Wavelength = ?

From (1)

v = n × λ

Rewriting the equation for λ, we get

λ = \frac{v}{n}

Substituting the values of v and n, we get

λ = \frac{v}{n} =\frac{290}{770} = 0.3767 \ m

Hence, the wavelength of sound wave is equal to 0.3767 m

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You set a tuning fork into vibration at a frequency of 723 Hz and then drop it off the roof of the Physics building where the ac
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Answer:

Explanation:

Given

Original Frequency f=723\ Hz

apparent Frequency f'=697\ Hz

There is change in frequency whenever source move relative to the observer.

From Doppler effect we can write as

f'=f\cdot \frac{v-v_o}{v+v_s}

where  

f'=apparent frequency  

v=velocity of sound in the given media

v_s=velocity of source

v_0=velocity of observer  

here v_0=0

697=723\cdot (\frac{343-0}{343+v_s})

v_s=(\frac{f}{f'}-1)v

v_s=(\frac{723}{697}-1)\cdot 343

v_s=12.79\approx 12.8\ m/s

i.e.fork acquired a velocity of 12.8 m/s

distance traveled by fork is given by

v^2-u^2=2as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

v_s^2-0=2\times 9.8\times s

s=\frac{12.8^2}{2\times 9.8}

s=8.35\ m

                                       

5 0
3 years ago
At T = 0C and p = 1000mb, 1 g of dry air receives an amount of heat during an isochoric process. It is then observed that its p
Rufina [12.5K]

Answer:

ΔT = 13.65° C

ΔQ = 13.7 J

Explanation:

First we will find the final temperature of air by using equation of state:

P₁V₁/T₁ = P₂V₂/T₂

For Isochoric Process, V₁ = V₂

Therefore,

P₁/T₁ = P₂/T₂

T₂ = P₂T₁/P₁

where,

T₂ = Final Temperature = ?

P₂ = Final Pressure = 1050 mb

P₁ = Initial Temperature = 1000 mb

T₁ = Initial Temperature = 0°C = 273 k

Therefore,

T₂ = (1050 mb)(273 K)/(1000 mb)

T₂ = 286.65 K

Change in Temperature = ΔT = T₂ - T₁

ΔT = 286.65 K - 273 K

<u>ΔT = 13.65° C</u>

<u></u>

The first law of thermodynamics can be written as:

ΔQ = ΔU + W

where,

ΔQ = heat absorbed

ΔU = change in internal energy = mCΔT

W = Work Done = 0 (in case of isochoric process)

Therefore.

ΔQ = mCΔT

where,

m = mass of air = 1 g = 1 x 10⁻³ kg

C = specific heat of dry air = 1003.5 J/kg.°C

Therefore,

ΔQ = (1 x 10⁻³ kg)(1003.5 J/kg.°C)(13.65°C)

<u>ΔQ = 13.7 J</u>

7 0
3 years ago
Gabriel is performing an experiment in which he is measuring the energy and work being done by a ball rolling down a hill. Which
melamori03 [73]

Answer:

They will both be recorded in Joules

Explanation:

- The energy of an object refers in general to the mechanical energy of the object, which is the sum of its kinetic energy (KE), which is the energy of motion, and of its potential energy (PE), which is the energy due to its position above the ground:

E=PE+KE

- The work done by an object is equal to the product between the force exerted by the object, F, and the displacement, d:

W=Fd (1)

The SI units of the energy is the Joules, J. The basic equivalence with SI units can be seen from the definition of kinetic energy:

KE=\frac{1}{2}mv^2

where

m is the mass, measured in kilograms (kg)

v is the speed, measured in meters per second (m/s)

So we have, since the speed is squared

1 J = 1 kg\cdot \frac{m^2}{s^2}

Now we can check from eq.(1) that the work as the same units. In fact, the force is measured in Newtons (N), and we know that force is equal to mass times acceleration, so we have:

1 N = 1 kg \cdot \frac{m}{s^2}

Distance is measured in meters (m), so the work is measured in

[W]=[kg \cdot \frac{m}{s^2}][m]=[kg\cdot \frac{m^2}{s^2}]

Which corresponds to the definition of Joule. Therefore, both energy and work are measured in Joules.

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