A 500-kg roller coaster car travels with some initial velocity along a track that is 5 m above the ground. The car goes down a s
1 answer:
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<h2>Answer: 26,8 s</h2>
Explanation:
If we are talking about an acceleration at a constant rate , we are dealing with constant acceleration, hence we can use the following equations:
(1)
(2)
Where:
is the final velocity of the plane (the takeoff velocity in this case)
is the initial velocity of the plane (we know it is zero because it starts from rest)
is the constant acceleration of the plane to reach the takeoff velocity
is the distance of the runway
is the time
Knowing this, let's begin with (1):
(3)
(4)
(5)
Substituting (5) in (2):
(6)
Finding :
This is the time needed to take off
Answer:
To make it into the pool you must run and jump at
Explanation:
Horizontal Launch
When an object is thrown with a specified initial speed in the horizontal direction, it describes a curved path that finishes when it hits the ground level after traveling certain horizontal distance x and a vertical height y from the launching point. The horizontal speed is always constant and the vertical speed increases due to the effect of gravity. It can be found that the horizontal distance reached by the object when launched at an initial speed in a given time t is
And the vertical distance is
If t is the total flight time, then x and y are maximum and we can find a relation between them. Solving for t in the first equation
Substituting in the second equation
Rearranging
Solving for
There are many applications for the horizontal launch. One common situation is when someone wants to drop something on certain terrain at a specific approximate point when traveling in a plane at a given height. Once the object is left fall, it has the same speed as the plane, so the plane speed can be estimated to make the best possible launch, or given that speed, we can know in advance where the object will reach ground level