Find the midpoint between (-9, 3) and (5, 7). PLEASE SOLVE THIS QUICK!! DUE IN AN HOUR
2 answers:
We know that mid - point of a line segment divides it into two equal parts, that is it divides the segment in the ratio of 1 : 1, so let's find the coordinates of the mid point of line segment joining points (-9 , 3) and (5 , 7).
let the coordinates of the points be x and y, now
Using section formula :
value of x :
value of y :
So, coordinates of the point which is midpoint of the given line is :
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Answer:
Below, you can see the graph of the function:
f(x) = x + cos(k*x)
for different values of k, as follows:
red: k = 1
green: k = 2
orange: k = 0.
Now let's find the values of k such that our function does not have local maxima nor local minima.
First, remember that for a given function f(x), the local maxima or minima points are related to the zeros of the first derivate of f(x).
This means that if:
f'(x0) = 0.
Then x0 is a maxima, minima or an inflection point.
Then if a function is such that the f'(x) ≠ 0 , ∀x, then this function will not have local maxima nor minima.
Now we have:
f(x) = x + cos(k*x)
then:
f'(x) = 1 - k*sin(k*x)
This function will be zero when:
1 = k*sin(k*x)
1/k = sin(k*x)
now, remember that -1 ≤ sin(θ) ≤ 1
then if 1/k is smaller than -1, or larger than 1, we will not have zeros.
And this will happen if -1 < k < 1.
Answer: 5:4
Step-by-step explanation:
Given : The number of convertibles = 1960
The number of minivans = 490
Total cars = 2450
The ratio of A to B can also be written as .
The ratio of cars to convertibles =
Hence, the ratio of cars to convertibles = 5:4