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Anton [14]
3 years ago
5

Find the midpoint between (-9, 3) and (5, 7). PLEASE SOLVE THIS QUICK!! DUE IN AN HOUR

Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0

Answer:

(-2,5)

Step-by-step explanation:

Tasya [4]3 years ago
5 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

We know that mid - point of a line segment divides it into two equal parts, that is it divides the segment in the ratio of 1 : 1, so let's find the coordinates of the mid point of line segment joining points (-9 , 3) and (5 , 7).

let the coordinates of the points be x and y, now

  • m = 1

  • n = 1

  • x_2 = 5

  • x_1 =  - 9

  • y_2 = 7

  • y_1 = 3

Using section formula :

value of x :

  • x =  \dfrac{mx_2 - nx_1}{m + n}

  • x =  \dfrac{(1 \times 5) - (1 \times  - 9)}{1 + 1}

  • x =  \dfrac{5 - ( - 9)}{2}

  • x =  \dfrac{5 + 9}{2}

  • x =  \dfrac{14}{2}

  • x = 7

value of y :

  • y =  \dfrac{my_2 -ny_1 }{m+ n}

  • y =  \dfrac{(1 \times 7) - (1 \times 3)}{1 + 1}

  • y =  \dfrac{7 - 3}{2}

  • y =  \dfrac{4}{2}

  • y = 2

So, coordinates of the point which is midpoint of the given line is :

\boxed{ \boxed{ (7, 2)}}

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Step-by-step explanation:

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The Coefficient of determination ( R^2) =?

The Coefficient of determination (R^2) is the squared value of the linear correlation Coefficient value (R) . The value value ranges from 0 to 1 and depicts the proportion of the variation in the dependent variable that can be accounted for by the independent variable.

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The Coefficient of determination (R^2) = 0.464^2 = 0.215296 = (0.215296 * 100%) = 21.5%

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