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Anton [14]
3 years ago
5

Find the midpoint between (-9, 3) and (5, 7). PLEASE SOLVE THIS QUICK!! DUE IN AN HOUR

Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0

Answer:

(-2,5)

Step-by-step explanation:

Tasya [4]3 years ago
5 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

We know that mid - point of a line segment divides it into two equal parts, that is it divides the segment in the ratio of 1 : 1, so let's find the coordinates of the mid point of line segment joining points (-9 , 3) and (5 , 7).

let the coordinates of the points be x and y, now

  • m = 1

  • n = 1

  • x_2 = 5

  • x_1 =  - 9

  • y_2 = 7

  • y_1 = 3

Using section formula :

value of x :

  • x =  \dfrac{mx_2 - nx_1}{m + n}

  • x =  \dfrac{(1 \times 5) - (1 \times  - 9)}{1 + 1}

  • x =  \dfrac{5 - ( - 9)}{2}

  • x =  \dfrac{5 + 9}{2}

  • x =  \dfrac{14}{2}

  • x = 7

value of y :

  • y =  \dfrac{my_2 -ny_1 }{m+ n}

  • y =  \dfrac{(1 \times 7) - (1 \times 3)}{1 + 1}

  • y =  \dfrac{7 - 3}{2}

  • y =  \dfrac{4}{2}

  • y = 2

So, coordinates of the point which is midpoint of the given line is :

\boxed{ \boxed{ (7, 2)}}

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  • 5x-2y+3x+2y

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2 years ago
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Triss [41]

1. w=2

2. x=2

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3 years ago
Suppose you flipped a coin and then rolled a six-sided die. What is the probability of landing on
stealth61 [152]

Answer:

1/12

Step-by-step explanation:

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Hope this helped!

6 0
3 years ago
9!-4!(5!) How do i solve?
Lemur [1.5K]
To simply the expression,we should remember an ! in math represents every number (til 1) before that one multiplied or "the product of the integers from 1 to n"

So now that we have the definitions we can simplify by finding the values of each:

(9x8x7x6x5x4x3x2x1)-(4x3x2x1)(5x4x3x2x1)

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3 years ago
Use the sample data and confidence level to construct the confidence interval estimate of the population proportion p. n equals
Alekssandra [29.7K]

Answer:

(0.767,0.833)

Step-by-step explanation:

The 95% confidence interval for population proportion p can be computed as

p-z_{\frac{\alpha }{2} } \sqrt{\frac{pq}{n} }

The z-value associated with 95% confidence level is 1.96.

whereas p=x/n

We are given that x=440 and n=550.

p=440/550=0.8

0.8-1.96\sqrt{\frac{0.8(0.2)}{550} }

0.8-1.96\sqrt{\frac{0.16}{550} }

0.8-1.96\sqrt{0.00029 }

0.8-1.96(0.01706)

0.8-0.03343

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Thus, the required confidence interval is

0.767<P<0.833  (rounded to 3 decimal places)

Hence, we are 95% confident that our true population proportion will lie in the interval (0.767,0.833)

3 0
3 years ago
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