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2 years ago

F(x) = -x^3+ 6x – 7 at x = 2

Mathematics

1 answer:

vodomira [7]2 years ago

4 0

Answer:

f(2)= -4

Step-by-step explanation:

f(x)= -x^3 + 6x - 7

f(2) = -2^3 + 6*2 - 7

f(2)= -8 +12 -7

f(2)= 3-7

f(2)= -4

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GIVEN BRAINLIEST, 5 STARS, + THANKS

Ede4ka [16]

Answer:

Option B. Side YZ is the same length as side Y'X'.

Step-by-step explanation:

XYZ is reflected across the y-axis and then translated down 6 units to form X'Y'Z'.

So, X' is the image of point X

Y' is the image of point Y

Z' is the image of point Z

And ΔXYZ ≅ ΔX'YΔ'Z'

And the corresponding length are congruent

We will check the options:

A. X has the same measure as X'. ⇒ True

B. Side YZ is the same length as side Y'X'. ⇒ Wrong

Because YZ will be translated to Y'Z'

C. Z has the same measure as Z'. ⇒ True

D. Side XZ is the same length as side X'Z'. ⇒ True

So, The answer is option B. Side YZ is the same length as side Y'X'.

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2 years ago

Which of the following equations is equivalent to 2/3 x - 1/2 y = 6? 2x - y = 6 2x - y = 36 4x - 3y = 36

boyakko [2]

Answer: THE LAST OPTION

Step-by-step explanation:

1. You have the following equation given in the problem:

$\frac{2}{3}x-\frac{1}{2}y=6$

2. If you multiply both sides of the equation shown above by 6, you obtain the following:

$\frac{2*6}{3}x-\frac{1*6}{2}y=6*6$

$\frac{12}{3}x-\frac{6}{2}y=36$

3. When you simplify the equation, you obtain the following equivalent equation:

$4x-3y=36$

5 0

3 years ago

Circle X with a radius of 6 units and circle Y with a radius of 2 units are shown. Which steps would prove the circles similar?

SSSSS [86.1K]

Answer:

See bolded below.

Step-by-step explanation:

Take a look at the attachment below. It represents circle x and y, with respect to each of their radii. In each of the options we are given, we would have to translate and dilate the circles, by a fixed scale factor -

Now the first thing one would do is translate the circles so that they share a common center point, or in other words the center of one circle rests on the edge of the other circle. That way when dilating circle y, it may fit into circle x as it expands.

The second point is how much this smaller circle ( circle y ) has to expand. The radius of circle y being 2, has to increase by 3 times the value to equal the radius of circle x, and hence has to dilate by a scale factor of 3 as to match circle x,

Solution = " Translate the circles so the center of one circle rests on the edge of the other circle, and dilate circle Y by a scale factor of 3 " / Option D