All categories

3 years ago

NEED HALP ASAP WILL GIVE BRAINLY

Mathematics

1 answer:

Debora [2.8K]3 years ago

8 0

Answer:

350 cm

Step-by-step explanation:

You might be interested in

Without graphing, find the equation of a line that is perpendicular to the line y = 2x + 3 and runs through the point (-2,5)

timofeeve [1]

I honestly had problems with these myself but if I had to guess I would put down 2|3

3 0

3 years ago

in question 9-12,determine if the equation of the line is in point-slope form or slope-intercept form and determine the slope of

rusak2 [61]

9 and 12 are slope-intercept form and 10 and 11 are point-slope form

4 0

3 years ago

It is required to make 14 grams of certain chemical compound called Z. This is made from compounds W, X, and Y in the ratio of 2

dexar [7]

Answer:

W = 9.33 grams

X = 4.67 grams

Step-by-step explanation:

Given;

Mass of Z to be made = 14 grams

Composition of Z

W:X:Y = 2:1:3

To make 6 grams of Y requires 4 grams of W and 2 grams of X

Composition of Y (for 6grams)

W:X = 4:2 = 2:1

Substituting the composition of Y to Z

Z = W:X:Y = 2:1:3

Z = W:X:W:X = 2:1:2:1

summing them up, we have;

Z = W:X = 4:2 = 2:1

Since the final mixing ratio for W and X are 2:1, to make 14 grams of Z, we need;

W = 2/3 × 14grams = 28/3 grams

W = 9.33 grams

X = 1/3 × 14grams = 14/3 grams

X = 4.67 grams

8 0

3 years ago

Bonjour pourriez vous m'aider avec cette équation du second degré? j'ai du mal à comprendre le concept. merci

olga_2 [115]

If a quadratic equation has solutions, the standard procedure will always work: given an equation like

$ax^2+bx+c=0$

The solutions (if any) are given by

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In your case, you have

$a=-9,\ b=0,\ c=1$

So the formula becomes

$x_{1,2} = \dfrac{\pm\sqrt{36}}{18}= \pm\dfrac{6}{18}=\pm\dfrac{1}{3}$

Anyway, this is quite a special case, because you're missing the linear term (since $b=0$ )

This means that you can solve equations like these more easily: rearrange the equation to make it look like $ax^2=c$ . In your case, it becomes

$9x^2=1$

Divide both sides by 9:

$x^2=\dfrac{1}{9}$

Now, you know that the square of a number equals 1/9. By definition, it means that this number is the square root of 1/9. Nevertheless, both the square root and its opposite are solutions of the equation, because the minus sign will cancel out when squaring.

So, in general, you have

$ax^2=c \iff x^2 = \dfrac{c}{a} \iff x=\pm\sqrt{\dfrac{c}{a}$

which of course makes sense, if you're using real numbers, only if c/a>0.

In your case, this becomes

$9x^2=1 \iff x^2 = \dfrac{1}{9} \iff x=\pm\sqrt{\dfrac{1}{9}} = \pm\dfrac{1}{3}$

3 0

3 years ago

Help please

Schach [20]

Answer:

192

Step-by-step explanation:

3(pi) x 4^2 x 12 ÷ 3 = 192

3 0

3 years ago