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3 years ago

Calculate the interest produced by a principal of $ 4,500 at 5% annual simple interest in 8 months.

Mathematics

1 answer:

enyata [817]3 years ago

5 0

Answer:

4,500 x 5 = 22,500

4,500 divided by 5 = 900

4,500 plus 5 = 4,505

4,500 minus 5 = 4,495

Step-by-step explanation:

it is either one of those that u have to choose from good luck

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The full question is shown below

a_sh-v [17]

Answer:

n = 3

Step-by-step explanation:

Ratio from Triangle A to Triangle B is 2:1.

n+2 = 5

n = 3

8 0

2 years ago

Jamie has a cup holder that can hold 3 cups at a time. The cup holders are labeled a, b, and c. He has 3 different color cups (b

JulsSmile [24]

Answer:

6 ways.

Step-by-step explanation:

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8 0

2 years ago

the first term of an arithmetic sequence is 10 and the sum of the first five terms is 250,find the sequence

Crazy boy [7]

Answer:

The sequence is:

10, 30, 50, 70, 90.....................

Step-by-step explanation:

We have,

First term (a) = 10

Common difference (d) = ?

Sum of first 5 terms ( $S_{5}$ ) = 250

or, $\frac{n}{2} [{2a+(n-1)d}] = 250$

or, $\frac{5}{2} [2*10 + 4d]=250$

or, $\frac{5}{2} * 4[5+d]=250$

or, 10(5 + d) =250

or, 5 + d = 25

∴ d = 20

Now,

2nd term = a + d = 10 + 20 = 30

3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50

4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70

5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90

8 0

2 years ago

Show whether or not y=x+3 is tangential to the curve y^2=x

wolverine [178]

The line y = x + 3 has slope 1, so we look for points on the curve where the tangent line, whose slope is dy/dx, is equal to 1.

y² = x

Take the derivative of both sides with respect to x, assuming y = y(x) :

2y dy/dx = 1

dy/dx = 1/(2y)

Solve for y when dy/dx = 1 :

1 = 1/(2y)

2y = 1

y = 1/2

When y = 1/2, we have x = y² = (1/2)² = 1/4. However, for the given line, when y = 1/2, we have x = y - 3 = 1/2 - 3 = -5/2.

This means the line y = x + 3 is not a tangent to the curve y² = x. In fact, the line never even touches y² = x :

x = y² ⇒ y = y² + 3 ⇒ y² - y + 3 = 0

has no real solution for y.

3 0

2 years ago

If the coordinates of the endpoints of a diameter of the circle are known, the equation of a circle can be found. First, find

Evgesh-ka [11]

Answer:

The equation of the circle is $(x+3)^2+(y-5)^2 = 17$

Step-by-step explanation:

The complete question is

If the coordinates of the endpoints of a diameter of the circle are known, the equation of a circle can be found. First, find the midpoint of the diameter, which is the center of the circle. Then find the radius, which is the distance from the center to either endpoint of the diameter. Finally use the center-radius form to find the equation.

Find the center-radius form of the circle having the points (1,4) and (-7,6) as the endpoints of a diameter.

Consider that, if both points are the endpoints of a diameter, the center of the circle is the point that is exactly in the middle of the two points (that is, the point whose distance to each point is equal). Given points (a,b) and (c,d), by using the distance formula, you can check that the middle point is the average of the coordinates. Hence, the center of the circle is given by

$(\frac{1-7}{2}, \frac{4+6}{2}) = (-3,5)$ .

We will find the radius. Recall that the radius of the circle is the distance from one point of the circle to the center. Recall that the distance between points (a,b) and (c,d) is given by $\sqrt[]{(a-c)^2+(b-d)^2}$ . So, let us use (1,4) to calculate the radius.

$r = \sqrt[]{(1-(-3))^2+(4-5)^2} = \sqrt[]{17}$ .

REcall that given a point $(x_0,y_0)$ . The equation of a circle centered at the point $(x_0,y_0)$ is

$(x-x_0)^2+(y-y_0)^2 = r^2$

In our case, $(x_0,y_0)=(-3,5)$ and $r=\sqrt[]{17}$ . Then, the equation is

$(x-(-3))^2+(y-5)^2 = (x+3)^2+(y-5)^2 = 17$

4 0

2 years ago