5 and 6 find the least common multiple of each set of number

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result:

$\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}$ .

Therefore:

$\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}$ .

Lookup $0.1985$ on a normal distribution table. The corresponding $z$ -score is $0.52$ . (In other words, $P(0 \le Z \le 0.52) = 0.1985$ .)

Given that

$z = 0.52$ ,
$x =5$ , and
$\sigma = 2$ ,

Solve the equation $\displaystyle z = \frac{x - \mu}{\sigma}$ for the mean, $\mu$ :

$\displaystyle 0.52 = \frac{5 - \mu}{2}$ .

$\mu = 5 - 2 \times 0.52 = 3.96$ .

3 0

3 years ago

What is the solution to the system of linear equations?

Rudik [331]

6x + 7y = 59...multiply by -4
4x + 5y = 41...multiply by 6

7 0

4 years ago

Read 2 more answers

Evaluate 7(-4) - |-6| + |4| <br> A. 13<br> B.-18<br> C. -30

tester [92]

Hello there!

Answer: ⇒ C. -30

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Step-by-step explanation:

First you had to remove parenthesis.

$-7*4-|-6|+|4|$

Then you multiply by the number.

$=-28-|-6|+|4|$

Apply absolute value.

$|-6|=6$

$=-28-6+|4|$

Again apply absolute value.

$|4|=4$

$=-28-6+4$

Simplify it's should be the correct answer.

$=-30$

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Hope this helps!

Thank you for posting your question at here on brainly.

Have a great day!

-Charlie

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8 0

3 years ago

The expression x^4-16 is equivalent to the product of (x+2) and p(x) which expression could represent p(x)

bagirrra123 [75]

Easy
differnce of 2 perfect squares
a²-b²=(a+b)(a-b)

in this case
x⁴=(x²)²
16=4²

(x²)²-4²=(x²+4)(x²-4)
x²-4 can be factored since 4=2²
x²-2²=(x+2)(x-2)

complete factored form is
(x²+4)(x+2)(x-2)
gegroup to seperate (x+2)
(x+2)[(x²+4)(x-2)]
(x+2)p(x)

p(x)=(x²+4)(x-2)
expanded
p(x)=x³-2x²+4x-8

3 0

3 years ago

PLEASE HELP On the number line, graph the solution to the inequality -5(x+1) > 7x + 31? Can you tell me how to go about doing

elena-s [515]

Answer:

I don't know how to insert a number line, but you have to put on it x<-3. You have to plot it, then put a open circle at -3, and draw an arrow, pointing it farther into the negitive side of the number line.

Step-by-step explanation:

3 0

3 years ago