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BARSIC [14]
3 years ago
12

Solve the equation to find where the treste ground levelEnter your answers from least to greatest and round to the nearest The m

eets the ground at and
Mathematics
1 answer:
DaniilM [7]3 years ago
7 0

Answer:

The trestle meets ground level at 0.875 units and 9.125 units

Step-by-step explanation:

Poorly formatted question.

The given equation is:

y = -x^2 + 10x - 8

Required

The point where the trestle gets to the ground level

To do this, we set y = 0

So, we have:

-x^2 + 10x - 8 = 0

Multiply through by -1

x^2 -10x + 8 = 0

Solve using quadratic formula:

x= \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

Where:

a = 1; b =-10; c = 8

So, we have:

x= \frac{-(-10) \± \sqrt{(-10)^2 - 4*1*8}}{2*1}

x= \frac{-(-10) \± \sqrt{68}}{2*1}

x= \frac{-(-10) \± 8.25}{2}

x= \frac{10 \± 8.25}{2}

Solve the fraction

x= 5 \± 4.125

Split

x= 5 + 4.125\ or\ x= 5 - 4.125

x= 9.125\ or\ x= 0.875

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Description

DescriptionIn mathematics, a zero of a real-, complex-, or generally vector-valued function, is a member of the domain of such that vanishes at; that is, the function attains the value of 0 at, or equivalently, is the solution to the equation. A "zero" of a function is thus an input value that produces an output of

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