Question

Solve the equation to find where the treste ground levelEnter your answers from least to greatest and round to the nearest The meets the ground at and

Answer 1

Answer:

The trestle meets ground level at 0.875 units and 9.125 units

Step-by-step explanation:

Poorly formatted question.

The given equation is:

$y = -x^2 + 10x - 8$

Required

The point where the trestle gets to the ground level

To do this, we set $y = 0$

So, we have:

$-x^2 + 10x - 8 = 0$

Multiply through by -1

$x^2 -10x + 8 = 0$

Solve using quadratic formula:

$x= \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where:

$a = 1; b =-10; c = 8$

So, we have:

$x= \frac{-(-10) \± \sqrt{(-10)^2 - 4*1*8}}{2*1}$

$x= \frac{-(-10) \± \sqrt{68}}{2*1}$

$x= \frac{-(-10) \± 8.25}{2}$

$x= \frac{10 \± 8.25}{2}$

Solve the fraction

$x= 5 \± 4.125$

Split

$x= 5 + 4.125\ or\ x= 5 - 4.125$

$x= 9.125\ or\ x= 0.875$