May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
-2 - 3 -(-4)= -2 - 3 + 4
-2 - 3 + 4
-5 + 4
= -1
Answer:
x=0
Step-by-step explanation:
We are given:
g(x) =10x +2
and
g(x)=2
g(x) is equal to both 10x+2 and 2. Therefore, by substitution, we can set them equal to each other
10x+2=2
Now, we need to solve for x. First, move all the numbers to the same side. Subtract 2 from both sides
10x+2-2=2-2
10x=0
To solve for x, we have to get x by itself. x and 10 are being multiplied. To get x alone, divide both sides by 10.
10x/10=0/10
x=0
Answer:
Volume of the cone: 32π cubed unit
Step-by-step explanation:
Volume of cone: V=1/3hπr²
1/3 x 6 x π x 4^2 = 32π
x = 32
To find the media, you take the middle number. If there is no discrete middle number, take the sum of the two closest to the middle and divide by 2.
(24 + x)/2 = 28
Multiply by 2 on both sides to get:
24 + x = 56
Subtract 24 from both sides to isolate the variable:
x = 56 - 24
x = 32
