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sweet [91]
3 years ago
15

Yeah

Mathematics
1 answer:
GuDViN [60]3 years ago
8 0

thats joy in my heart

Step-by-step explanation:

thank you

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Jose ran13 mile in 3 minutes and 15 seconds. Calculate Jose's rate in minutes per mile; in other words, the time that it would t
Alexus [3.1K]

Answer:

1 mile = 15 seconds

Step-by-step explanation:

3 minutes and 15 seconds = 3 min + 15 sec

1 minute = 60 seconds

15 seconds =15/60 = 0,25 min

then

3minutes and 15 seconds = 3.25 minutes

13miles in 3 minutes and 15 seconds

= 13 miles / 3.25 minutes

= 4 miles / 1 minute

every minute Jose ran 4 miles

then:

4 miles is a 1 minute

1 mile is a T minutes

T = 1*1/4

T = 1/4 minute

1 minute = 60 secomds

1/4 minute = 60*1/4 = 60/4 = 15 seconds

7 0
4 years ago
Read 2 more answers
5/6 divided by 10/11
larisa [96]

Answer:

11/12

Step-by-step explanation:

7 0
3 years ago
1.)The angle θ lies in Quadrant IV. sinθ=−2/3 What is cosθ?
AveGali [126]

Answer:

1. From sin²θ +cos²θ =1 and sinθ=-2/3, we see that cosθ=√(1-sin²θ) or cosθ=√5/3, where the sign of cosine is positive as it is in Quadrant IV. x lies in 4th quadrant , cos x is +ve. , cos x = √5/3. Answer.

answer : cos x = √5/3

2.  4/3

3.  sin (- theta)  = - sin (x)        so sin x = 1/6

 tan = sin / cos   =  1/6  /  cos  =  - sqrt35/35     solve for cos

                        cos =  1/6 * (-35/sqrt35)

                       

                                  = -35 sqrt35 /210

answer : −35/√210

4. The cosine function is an even function, so cos(θ) = cos(-θ).

The relationship between sin(θ) and cos(θ) is sin(θ) = ±√(1 -cos(θ)^2)

For sin(θ) < 0 and cos(θ) = (√3)/4,  sin(θ) = -√(1 -3/16) = -√(13/16)

sin(θ) = -(√13)/4   For sin(θ) < 0 and cos(0) = √(3/4), ...

sin(θ) = -√(1 -3/4) = -√(1/4)       sin(θ) = -1/2

answer : -13/√4

5.  answer : tan^2 θ ⋅ cos^2 θ = 1 − cos^2 θ would be the first step

4 0
4 years ago
For circle C, CG = CE, CG is perpendicular to FB, and CE is perpendicular to DA. What conclusion can be made? a circle with cent
svetlana [45]

Answer:

A circle with center C has chords FB and DA which are equidistant from C.

Step-by-step explanation:

A chord is a straight line drawn from a point on the circumference of a circle to another point on the circumference, without passing through the center of the circle.

From the given question, a circle center C has two chords FB and DA that are equidistant from the center of the circle. The distant of FB from C is CG and the distance of DA from C is CE. But CG = CE, which implies that the two chords have equal distant from the center of the circle.

Therefore line CG from center C intersects FB at G, and line CE from center C intersects DA at E.

8 0
4 years ago
Parallel Lines
Liono4ka [1.6K]
Here is the answer, the slope for both lines are the same B(or C) is just different.

7 0
4 years ago
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