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romanna [79]
3 years ago
15

What is the simplified form of the fifth root of x to the fourth power times the fifth root of x to the fourth power?

Mathematics
2 answers:
Lynna [10]3 years ago
4 0

Answer:

<em>The simplified form will be:  x\sqrt[5]{x^3}</em>

Step-by-step explanation:

The given expression is:   \sqrt[5]{x^4}*\sqrt[5]{x^4}

Simplifying the above expression......

\sqrt[5]{x^4}*\sqrt[5]{x^4}\\ \\ =\sqrt[5]{x^4*x^4}\\ \\ =\sqrt[5]{x^4^+^4}\ [Exponents\ gets\ added\ while\ multiplication]\\ \\ =\sqrt[5]{x^8}\\ \\ =\sqrt[5]{x^5*x^3}\ [As\ 5+3=8] \\ \\ =\sqrt[5]{x^5}*\sqrt[5]{x^3}\\ \\ =x\sqrt[5]{x^3}

So, the simplified form will be:  x\sqrt[5]{x^3}

Ray Of Light [21]3 years ago
3 0
\bf \sqrt[5]{x^4}\cdot \sqrt[5]{x^4}\implies \sqrt[5]{x^4\cdot x^4}\implies \sqrt[5]{x^{4+4}}\implies \sqrt[5]{x^8}\implies \sqrt[5]{x^{5+3}}&#10;\\\\\\&#10;\sqrt[5]{x^5\cdot  x^3}\implies x\sqrt[5]{x^3}
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A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

⇒ 2(x+y) = 42\\x+y = 21\\y = 21-x

width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

And ,

y = 21-x\\y = 21-11\\y = 10 inches

∴ Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

7 0
3 years ago
Given that curl F = 2yi – 2zj + 3k, find the surface integral of the normal component of curl F (not F) over (a) the open hemisp
Dimas [21]

Use Stokes' theorem for both parts, which equates the surface integral of the curl to the line integral along the surface's boundary.

a. The boundary of the hemisphere is the circle x^2+y^2=9 in the plane z=0, where the curl is \mathrm{curl}\vec F=2y\,\vec\imath+3\,\vec k. Green's theorem applies here, so that

\displaystyle\iint_S\mathrm{curl}\vec F\cdot\mathrm d\vec S=\int_{\partial S}\vec F\cdot\mathrm d\vec r=3\int_{x^2+y^2=9}\mathrm d\vec r

which means the value of the line integral is 3 times the area of the circle, or 27\pi.

b. The closed sphere has no boundary, so by Stokes' theorem the integral is 0.

7 0
3 years ago
Marcelis takes a taxi to the airport. The taxi charges $2 per mile and an initial fee of
Marizza181 [45]

Answer:

13 miles

Step-by-step explanation:

27.50- 1.50(fee)=26.00 26/2(2$per mile)=13 miles

4 0
3 years ago
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velikii [3]

Answer:

d

Step-by-step explanation:

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The sales tax in your city is 8.8%, and an item costs $63 before tax.
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Answer: 5.54

Step-by-step explanation:

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tax paid = 63 * 0.088 = 5.54

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