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Debora [2.8K]
4 years ago
9

Determine the equation of the line, in point-slope form, that will get your spacecraft from Point A (0,3) to Point B (-3,0)

Mathematics
2 answers:
jeka944 years ago
6 0
m= \frac{y2-y1}{x2-x1}

m= \frac{0-3}{-3-0}

m= \frac{-3}{-3}

m=1

Point Slope Form:  (y-y1)=m(x-x1)

(y-3)=1(x-0)

(y-3)=(x-0)

(y-3)=(x)
Alenkinab [10]4 years ago
5 0
A (0,3), \ \ B (-3,0) \\\\\\ First \  find \ the \  slope \ of \ the \ line \ thru \  the \  points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} }  \\ \\m=\frac{ 0-3}{-3-0} = \frac{-3}{-3}=1 \\ \\   Use  \  point \  form  \ of  \ a \  line\  with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=1,\ \ x_{1}=0, \ \ y_{1}=3 \\ \\ y-3=  (x-0}\\\\y= x +3
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false

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A rectangle is placed around a semicircle as shown below. The length of the rectangle is 14mm. Find the area of the shaded regio
Damm [24]

Image is missing, so i have attached it

Answer:

21.07 mm²

Step-by-step explanation:

We will use the Formulas:

Area of semicircle = πr²/2

Area_rectangle = Length x width = Lw

We are given:

Length of rectangle = 14 mm

From the attached image, the diameter of the semicircle is equal to the length of the rectangle.

Thus;

diameter of semicircle = length of rectangle

Therefore,

diameter of semicircle = 14 mm

Also, from the attached image, the radius of the semicircle is equal to the width of the rectangle.

Thus;

diameter of semicircle/2 = radius of semicircle

Hence;

radius of semicircle = 14/2 = 7mm = width of rectangle

Thus;

Area of rectangle = L*w = 14 × 7 = 98 mm²

Area of semicircle = πr²/2 = π×7²/2 = 76.93 mm²

To get the area of the shaded region, we will subtract area of the semi-circle from the area of the rectangle.

Area of shaded region = Area_rectangle - Area_semicircle = 98 - 76.93 = 21.07 mm²

7 0
3 years ago
3. Classify each function according to whether it is a vertical stretch, a vertical compression, a horizontal
Vladimir79 [104]

The classifications of the functions are

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  • A vertical compression --- g(x) = 0.65f(x)
  • A horizontal stretch --- k(x) = f(0.5x)
  • A horizontal compression  --- h(x) = f(14x)

<h3>How to classify each function accordingly?</h3>

The categories of the functions are given as

  • A vertical stretch
  • A vertical compression
  • A horizontal stretch
  • A horizontal compression

The general rules of the above definitions are:

  • A vertical stretch --- g(x) = a f(x) if |a| > 1
  • A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
  • A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
  • A horizontal compression  --- g(x) = f(bx) if |b| > 1

Using the above rules and highlights, we have the classifications of the functions to be

  • A vertical stretch --- p(x) = 4f(x)
  • A vertical compression --- g(x) = 0.65f(x)
  • A horizontal stretch --- k(x) = f(0.5x)
  • A horizontal compression  --- h(x) = f(14x)

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I need answers for the questions in the picture
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