0.0000024 in scientific notation

Which of the following options have the same value as 96% of 25

Maru [420]

96% of 25 is 24 hope this helps

8 0

3 years ago

(CO6) From a random sample of 68 businesses, it is found that the mean time that employees spend on personal issues each week is

satela [25.4K]

Answer:

(1) (4.82, 4.98)

(2) Large sample size

(3) Yes, the temperature is within the confidence interval of (37.40, 37.60)

(4) (15.083, 15.117)

Step-by-step explanation:

Confidence Interval (CI) = mean + or - (t×sd)/√n

(1) mean = 4.9, sd = 0.35, n = 68, degree of freedom = n-1 = 68 - 1 = 67

t-value corresponding to 67 degrees of freedom and 95% confidence level is 1.9958

CI = 4.9 + (1.9958×0.35)/√68 = 4.98

CI = 4.9 - (1.9958×0.35)/√68 = 4.82

CI is (4.82, 4.98)

(2) Error margin = (t-value × standard deviation)/√sample size

From the formula above, error margin varies inversely as the square root of the sample size. Since the relationship between the error margin and sample size is inverse, increase in one (sample size) will conversely lead to a decrease in the other (error margin)

(3) mean = 37.5, sd = 0.6, n= 100, degree of freedom = n-1 = 100-1 = 99

t-value corresponding to 99 degrees of freedom and 90% confidence level is 1.6602

CI = 37.5 + (1.6602×0.6)/√100 = 37.5 + 0.10 = 37.60

CI = 37.5 - (1.6602×0.6)/√100 = 37.5 - 0.10 = 37.40

37.53 is within the confidence interval (37.40, 37.60)

(4) mean = 15.10, sd =0.08, n = 104, degree of freedom = n-1 = 104-1 = 103

t-value corresponding to 103 degrees of freedom and 97% confidence interval is 2.2006

CI = 15.10 + (2.2006×0.08)/√104 = 15.10 + 0.017 = 15.117

CI = 15.10 - (2.2006×0.08)/√104 = 15.10 - 0.017 = 15.083

CI is (15.083, 15.117)

4 0

3 years ago

A family is relocating from St. Louis, Missouri, to California. Due to an increasing inventory of houses in St. Louis, it is tak

Dafna1 [17]

Answer:

a. Assume that the population has a normal distribution.

b. The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.

Step-by-step explanation:

Question a:

We have to assume normality.

Question b:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645\frac{35}{\sqrt{29}} = 10.69$

The lower end of the interval is the sample mean subtracted by M. So it is 230 - 10.69 = 219.31 days.

The upper end of the interval is the sample mean added to M. So it is 230 + 10.69 = 240.69 days.

The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.

7 0

3 years ago

Math hw graded on accuracy pls help!!

lubasha [3.4K]

Answer:

see below

Step-by-step explanation:

Putting n=1 into the formulas eliminates the first two choices, since they evaluate to 3.57 and 0.85, respectively, not 4.2.

Putting n=2 into the formula eliminates the third choice, because you know that 4.2(0.15) < 3.57 without even using a calculator.

The only viable choice (and the correct choice) is the last one.

8 0

4 years ago

Oliver removed 56 marbles from his marble

krok68 [10]

ANSWER:
Total marbles =56
Number of groups =8
Therefore number of marbles in each group =56/8
= 7 marbles in each group.
HOPE IT HELPS!!!!
PLEASE MARK BRAINLIEST !!!!

5 0

3 years ago

Read 2 more answers