If a1=10 and an=an-1+4 then find the value of a5
1 answer:
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Step-by-step explanation:
Since we have given that
Number of muffins Diana sold at the bake sale = 336
Number of muffins Bob sold at the bake sale = 287
Now, here we are using the method of estimation i.e. rounding the integers to nearest ones.
By estimation, we get
Number of muffins Diana sold at the bake sale = 340
Number of muffins Bob sold at the bake sale = 290
So,
Difference between them is given by
Hence, Bob sold 50 fewer muffins than Diana.
The cost of each senior ticket is $ 5 and cost of each child ticket is $ 12
<em><u>Solution:</u></em>
Let "a" be the price of each senior ticket
Let "b" be the price of each child ticket
<em><u>On the first day of ticket sales the school sold 4 senior tickets and 4 child tickets for a to total of 68</u></em>
Thus a equation is framed as:
4 senior tickets x price of each senior ticket + 4 child tickets x price of each child ticket = 68
4a + 4b = 68 ---------- eqn 1
<em><u>The school took in 120 on the second day by selling 12 senior tickets and 5 child tickets</u></em>
Similarly, we frame a equation as:
12a + 5b = 120 ---------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Multiply eqn 1 by 3</u></em>
12a + 12b = 204 -------- eqn 3
<em><u>Subtract eqn 2 from eqn 3</u></em>
12a + 12b = 204
12a + 5b = 120
( - ) --------------
7b = 84
b = 12
<em><u>Substitute b = 12 in eqn 1</u></em>
4a + 4(12) = 68
4a + 48 = 68
4a = 20
a = 5
Thus cost of each senior ticket is $ 5 and cost of each child ticket is $ 12
Answer:
30units,2900
Step-by-step explanation:
Given that Country Motorbikes Incorporated finds that it costs $400 to produce each motorbike, and that fixed costs are $1600 per day.
The price function is p(x) = 700 − 5x, where p is the price (in dollars) at which exactly x motorbikes will be sold.
If x units are produced and sold we have
Costs for x units = variable costs *x +Fixed costs
Sales revenue = no of units sold * price =
Profit funciton = P(x) = Sales revenue - Total cost
=
To get maximum profit we use derivative test I derivative =0 and II derivative =negative
Producing 30 units will maximize the profit.
Max profit
=P(30) = 2900