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3 years ago

Identify the domain and range of this graph

Mathematics

1 answer:

RSB [31]3 years ago

4 0

Answer:

domain is [-3,3] & range is [-3,3]

Step-by-step explanation:

When given a graph of a circle and ask to solve range and domain....

First: find the four points of the circle:

(-3,0);(3,0);(0,-3);(0,3) . **Best to plot these points on this graph to understand where the points are and what we are looking at.

Second: Look for range(vertical directions/left and right) and domain(horizontal direction/up and down).

domain: x-values, first coordinate (-3,0) & (3,0)

range: y-values, second coordinate (0,-3);(0,3)

Third: take what you know and solve domain and range*include bracket to show domain and range

domain is [-3,3] & range is [-3,3]

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Answer:

(A) There should have been 5 outcomes of HT

(B) The experimental probability is greater than the theoretical probability of HT.

Step-by-step explanation:

Given

$S = \{HH,HT,TH,TT\}$ -- Sample Space

$n(S) = 4$ --- Sample Size

Solving (a); theoretical outcome of HT in 20 tosses

First, calculate the theoretical probability of HT

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$P(HT) = \frac{1}{4}$

Multiply this by the number of tosses

$P(HT) * n= \frac{1}{4} * 20$

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Solving (b); experimental probability of HT

Here, we make use of the table

$P(HT) = \frac{n(HT)}{n(S)}$

$P(HT) = \frac{6}{20}$

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$P(HT) = \frac{1}{4}$

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By comparison;

$0.30 > 0.25$

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3 years ago

Can somebody please explain and answer this for me? I really don't get it.

Tcecarenko [31]

Answer:

Results can be $(-\frac{1}{3} )^5$

Step-by-step explanation:

-The solution for this question:

$(-\frac{1}{3} )^5$ is equal to $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$

-The calculation for $(-\frac{1}{3} )^5$ :

$(-\frac{1}{3} )^5 = -\frac{1}{243}$

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Observe the given figure.

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$\angle T + \angle R = 180 ^{\circ}$

Hence, the sum of the two angles is 180 degrees.

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Therefore, angle T and angle R are supplementary angles.

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Identify the domain and range of this graph​

Identify the domain and range of this graph