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zmey [24]
2 years ago
7

How do we solve this one​

Mathematics
1 answer:
Whitepunk [10]2 years ago
7 0

Answer:

how should I answer it?

Step-by-step explanation:

elimination,substitution, etc

answer will be in comments

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Alvin is 15 years younger than Elga. The sum of their ages is 25. What is Elga’s age
Fynjy0 [20]
Elga is 20 years old and Alvin would be 5. Hope this helped.
4 0
3 years ago
Graph y=-3x +7 and the line that is<br> parallel to it that passes through (4,1).
Brums [2.3K]
Y = -3x + 13

Steps and the graph are on paper

6 0
3 years ago
Please help answer and explanation im very confused.
Veseljchak [2.6K]

Answer:

1) 18m²

2) 25cm²

Step-by-step explanation:

1)

  • a = ½ × b × h
  • a = ½ × 9 × 4
  • a = ½ × 36
  • a = 18m²

2)

  • a = ½ × b × h
  • a = ½ × 10 × 5
  • a = 5 × 5
  • a = 25 cm²
6 0
2 years ago
Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.
Maru [420]

Answer:

9\text{ln}|x|+2\sqrt{x}+x+C

Step-by-step explanation:

We have been an integral \int \frac{9+\sqrt{x}+x}{x}dx. We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx

\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx

Now, we will apply the sum rule of integrals as:

\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx

9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx

Using common integral \int \frac{1}{x}dx=\text{ln}|x|, we will get:

9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx

Now, we will use power rule of integrals as:

9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx

9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2\sqrt{x}+\int 1dx

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

9\text{ln}|x|+2\sqrt{x}+x+C

Therefore, our required integral would be 9\text{ln}|x|+2\sqrt{x}+x+C.

4 0
2 years ago
The Wildcats in leopards are on evenly matched football teams when they play there is a .5 probability that the Wildcats win if
aliya0001 [1]

Answer:

P( x = 2) = 0.4

Or 40%

Step-by-step explanation:

Given that wildcat has 0.5 probability of winning if they play nine times 

Probability = possible outcomes ÷ required outcome

The required outcome = 9

Probability = 0.5

Let calculate the possible outcomes

Possible outcomes = 0.5 × 9 = 4.5 games

the probability that the Wildcats win two of the games will be

P( x = 2) = 2/4.5 = 0.44

Or 44%

8 0
2 years ago
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