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den301095 [7]
3 years ago
10

PLEASE HELP!!!!!! IM HORRIBLE AT MATHPLEASE PLEASE PLEASE PLEASE HELP!!!!!!!!​

Mathematics
1 answer:
iVinArrow [24]3 years ago
6 0

Answer:

2. No, the triangles can't be proven congruent

3. yes, SAS; Δ<em>STV</em> ≅ Δ<em>SUV</em>

4. yes, SSS; Δ<em>NMQ</em> ≅ Δ<em>NPQ</em>

5. No, the triangles can't be proven congruent

6. yes, SAS; Δ<em>XWZ</em> ≅ Δ<em>XYZ</em>

7. | <em>Reasons</em> |

   1. | <em>given</em> (note this is a <em>side</em>) |

   2. | <em>given</em> (note this is a <em>side</em>) |

   3. | <em>given</em> |

   4. | <em>definition of a midpoint</em> (a midpoint <em>bisects</em> the line it is one because it is <em>equidistant</em> from the two endpoints; basically, the two pieces of a line bisected by a midpoint will <em>always</em> be equal) |

   5. | <em>SSS Theorem</em> (the two givens beside the midpoint were two sets of equal corresponding sides; since we have three sets of corresponding sides equal, the theorem used here is the SSS Theorem) |

Step-by-step explanation:

Here's a quick review of the two theorems mentioned in this worksheet:

  • Side-Side-Side Theorem: in reference to <em>congruency</em>, this theorem states that if the three sides of one triangle are equal to the respective sides of another triangle, then the two triangles are congruent.
  • What about SAS? The letters are ordered in that way for a reason: the <em>Side-Angle-Side</em> Theorem tells us that if we have two triangles, and a set of two corresponding sides and their included angle are equal, then the triangles are congruent.
  1. By <em>included angle</em>, we mean the angle <u><em>between</em></u><em> two sides</em>.

I know, jaelee04, I'm sorry, this explanation is a bit short, but email me and I'll send you my full answer. The warning is that it's really long!

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Need answer please show work
Jet001 [13]

Let us set up some variabe:

  • height: h
  • base: b

Use the known information:

  • b = 2h + 8

Now lets find the area

   Area = (1/2) * b *h = (1/2) * h * (2h + 8)

Hope that helps!

7 0
2 years ago
Identify the name of the polygon given the number of sides.
Vesna [10]

Answer:

Step-by-step explanation:

3 Triangle

4 Quadrilateral

5 Pentagon

6 Hexagon

7 Heptagon

8 Octagon

9 Nonagon

10 Decagon

5 0
3 years ago
If AB = 13, BC = 9, and CA = 17, list the angles of ABC in order from smallest to largest.
svp [43]

Across the largest side is going to be largest angle, and across the smallest side -smallest angle.

Sides:

BC = 9 < AB = 13 < CA = 17.

Angles that are across sides: A < C < B.


Answer is d- A C B.

4 0
4 years ago
If the ratio of the length of segment AC to the length of segment CB is 3:1, what is the y-coordinate of point C?
Yuki888 [10]

Answer:

The coordinates of point C are (8,8.5)

Step-by-step explanation:

The picture of the question in the attached figure

Let

(C_x,C_y) ----> coordinates of point C

we have that

The horizontal distance AB is equal to

AB_x=10-2=8\ units

The vertical distance AB is equal to

AB_y=10-4=6\ units

Find the horizontal coordinate of point C

we know that

\frac{AC}{CB}=\frac{3}{1}

so

\frac{AC_x}{CB_x}=\frac{3}{1}

AC_x=3CB_x----> equation A

AC_x+CB_x=8 ----> equation B

substitute equation A in equation B

3CB_x+CB_x=8

4CB_x=8\\CB_x=2

AC_x=3(2)=6

so

The x-coordinate of point C is equal to the x-coordinate of point A plus the horizontal distance between the point A and point C

C_x=A_x+AC_x=2+6=8

Find the vertical coordinate of point C

we know that

\frac{AC}{CB}=\frac{3}{1}

so

\frac{AC_y}{CB_y}=\frac{3}{1}

AC_y=3CB_y----> equation A

AC_y+CB_y=6 ----> equation B

substitute equation A in equation B

3CB_y+CB_y=6

4CB_y=6\\CB_y=1.5

AC_y=3(1.5)=4.5

so

The y-coordinate of point C is equal to the y-coordinate of point A plus the vertical distance between the point A and point C

C_y=A_y+AC_y=4+4.5=8.5

therefore

The coordinates of point C are (8,8.5)

5 0
3 years ago
Pleaseee help im really confused
True [87]

Answer:

420 x .1 = 42

420 + 42 = 462

400 x .2 = 80

400 + 80 = 480

The first one is cheaper

4 0
3 years ago
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