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Firlakuza [10]
3 years ago
5

A store buys necklaces wholesale

Mathematics
1 answer:
Nitella [24]3 years ago
4 0

Answer:

9

Step-by-step explanation:

If the mark up is 75% then the price of a necklace is 56.7

the least they want to profit is 500

so the answer should be at least 9, because the price is over 55, which would be 550 if multiplied by 10

You might be interested in
Cosine law help! Really appreciate your guys hslp
Alexandra [31]
Answer: Either 25.0 or 25 depending on how your teacher wants you to format the answer

===========================================================

Explanation:

To start off, it probably helps to translate what the question wants. 
It states "For the pilot of airplane B, calculate the angle between the lines of sight to the airplane at C and Jenny's airplane [at point A]". 
This fairly long, and possibly complex, sentence boils down to "find angle B"

To find angle B, we need to find the length of side 'a' first

Let,
a = x
b = 4.2
c = 5.7

Note how the lowercase letters (a,b,c) are opposite their uppercase counterparts (A,B,C). This is often the conventional way to label triangles. The lowercase letters are usually for the side lengths while the upper case is for the angles.

We have angle A = 120 degrees

Plug these values into the law of cosines formula below. Then solve for x
a^2 = b^2 + c^2 - 2*b*c*cos(A)
x^2 = 4.2^2 + 5.7^2 - 2*4.2*5.7*cos(120)
x^2 = 17.64 + 32.49 - 47.88*cos(120)
x^2 = 17.64 + 32.49 - 47.88*(-0.5)
x^2 = 17.64 + 32.49 + 23.94
x^2 = 74.07
x = sqrt(74.07)
x = 8.60639297266863
x = 8.6064

So side 'a' is roughly 8.6064 kilometers when we round to four decimal places

Now we'll use this to find angle B
Use the law of cosines again, but this time, the formula is slightly altered so that angle B is the focus instead of angle A

Plug in the side lengths (a,b,c). Solve for angle B
b^2 = a^2 + c^2 - 2*a*c*cos(B)
(4.2)^2 = (8.6064)^2 + (5.7)^2 - 2*(8.6064)*(5.7)*cos(B)
17.64 = 74.07012096 + 32.49 - 98.11296*cos(B)
17.64 = 106.56012096 - 98.11296*cos(B)
17.64 - 106.56012096 = 106.56012096 - 98.11296*cos(B)-106.56012096
-88.92012096  = -98.11296*cos(B)
(-88.92012096)/(-98.11296)  = (-98.11296*cos(B))/(-98.11296)
0.906303519535034 = cos(B)
cos(B) = 0.906303519535034
arccos(cos(B)) = arccos(0.906303519535034)
B = 25.0005785532867

It's a bit messier this time around, but we get the approximate angle
B = 25.0005785532867
which rounds to
B = 25.0 degrees
when we round to the nearest tenth. We can write "25.0" as simply "25"

5 0
3 years ago
(4√3 − 2√5)(3√10 + 5√6) simplify show all work
bulgar [2K]

Answer:

2√30 + 30√2

Step-by-step explanation:

(4√3 − 2√5)(3√10 + 5√6) simplify

=======

  • (4√3 − 2√5)(3√10 + 5√6)=
  • 12√30 + 20√18 - 6√50 - 10√30=
  • 2√30 + 20*3√2 - 6*5√2=
  • 2√30 + 30√2
3 0
3 years ago
Read 2 more answers
Y=-3 using intercept and standard form
blondinia [14]

Answer:?

Step-by-step explanation:

6 0
3 years ago
One fifth of the sum of a number and -3 is twice the number
aleksley [76]

Answer:

x = \frac{-1}{3}

Step-by-step explanation:

Let the number be x.

\frac{1}{5} (x - 3) = 2x\\

x - 3 = 10x

9x = -3

x = \frac{-1}{3}\\

6 0
3 years ago
What is the perimeter in square units of the rectangle shown on the coordinate grid?
Rashid [163]

In order to find the Perimeter of the Rectangle, First we need to find the Length and Width of the Rectangle.

Distance between two points (x₁ , y₁) and (x₂ , y₂) is given by :

\bigstar\;\; \mathsf{Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}

There are two lengths in a rectangle. Let us find any one length of the rectangle.

I'm considering the length with co-ordinates (-8 , 2) and (-2 , 10)

Here :  x₁ = -8 and x₂ = -2 and y₁ = 2 and y₂ = 10

Substituting the values in the distance formula, We get :

\mathsf{\implies Length = \sqrt{[-2 - (-8)]^2 + [10 - 2]^2}}

\mathsf{\implies Length = \sqrt{[-2 + 8]^2 + [8]^2}}

\mathsf{\implies Length = \sqrt{[6]^2 + [8]^2}}

\mathsf{\implies Length = \sqrt{36 + 64}}

\mathsf{\implies Length = \sqrt{100}}

\mathsf{\implies Length = 10}

There are two widths in a rectangle. Let us find any one width of the rectangle.

I'm considering the width with co-ordinates (-2 , 10) and (2 , 7)

Here :  x₁ = -2 and x₂ = 2 and y₁ = 10 and y₂ = 7

Substituting the values in the distance formula, We get :

\mathsf{\implies Width = \sqrt{[2 - (-2)]^2 + [7 - 10]^2}}

\mathsf{\implies Width = \sqrt{[2 + 2]^2 + [-3]^2}}

\mathsf{\implies Width = \sqrt{[4]^2 + [-3]^2}}

\mathsf{\implies Width = \sqrt{16 + 9}}

\mathsf{\implies Width = \sqrt{25}}

\mathsf{\implies Width = 5}

Perimeter of a Rectangle is given by : 2[Length + Width]

:\implies  Perimeter of the given rectangle = 2[10 + 5]

:\implies  Perimeter of the given rectangle = 2[15]

:\implies  Perimeter of the given rectangle = 30

<u>Answer</u> : Perimeter of the given rectangle is 30 square units

4 0
3 years ago
Read 2 more answers
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