Answer:
<em> Anna's wand can cast 70 spells</em>
<em></em>
Step-by-step explanation:
Elsa's wand can cast 53 spells
her wand casts 17 fewer cells than her sister Anna's
Amount of spells cast by Anna's wand = ?
We write the question down in the form of an equation
where 
is the amount of spells Anna's wand can cast.
we then proceed to solve by collecting like terms to different sides of the equation. We'll have
which leaves us with
This means that<em> Anna's wand can cast 70 spells.</em>
Setup is
y = k/x
8 = k/3
k = 24
Now use 6 for y
6 = 24/x
x = 24/6 = 4 or A
Answer:
B.
Step-by-step explanation:
Well we know that
so we can get the 2 outside of the radical
and we can get the x^2 outside too.
and we also can get y outside.
so we have:
![2x^{2}y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=2x%5E%7B2%7Dy%5Csqrt%5B5%5D%7B7xy%5E3%7D)
Answer:
7 is the (constant) coefficient of 1/y, but no, it is not the coefficient of y
Step-by-step explanation:
7/y can be rewritten as 7(1/y) or as 7(y^[-1]). In this case, yes, 7 is the (constant) coefficient of 1/y, but no, it is not the coefficient of y.
Answer:
C) If the perfect square terms are A^2 and B^2 and other terms must be 2 AB and -2AB
Step-by-step explanation:
As,
