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Zina [86]
4 years ago
6

Convert each compound name into its chemical formula, then balance the equation. 1. aluminum chloride + calcium hydroxide  alum

inum hydroxide + calcium chloride
Chemistry
1 answer:
seraphim [82]4 years ago
3 0

Answer:

2AlCl3 + 3Ca(OH)2 --> 2Al(OH)3 + 3CaCl2

Explanation:

aluminum chloride + calcium hydroxide --> aluminum hydroxide + calcium chloride

AlCl3 + Ca(OH)2 --> Al(OH)3 + CaCl2

Note: Al forms an ion of charge +3, Cl forms ion of charge -1, OH forms ion of -1, and Ca forms ions of charge +2. So when you combine 2 of these into ions, (must be one positive, one negative for ionic compounds), make sure the net charge at the end =0.

For example, Al ions have a charge of +3, so it needs 3 Cl- ions to eliminate the negative charge, so aluminium chloride is AlCl3.

Now balance the equation. make sure both sides have the equal no. of ions.

start with Cl. the reactant side has 3 Cl ions, while the product side has 2. So, the lowest common multiple is 6. Multiply AlCl3 by 2, and CaCl2 by 3 to get 6 Cl ions on each side.

2AlCl3 + Ca(OH)2 --> Al(OH)3 + 3CaCl2

Now the reactant side has 2 Al ions. So, multiply the Al(OH)3 on the product side by 2 to balance out Al ions.

2AlCl3 + Ca(OH)2 --> 2Al(OH)3 + 3CaCl2

Finally, the product side has 6 OH- ions, so multiply 3 on Ca(OH)2 from the reactant side to balance out the OH- ions.

2AlCl3 + 3Ca(OH)2 --> 2Al(OH)3 + 3CaCl2

Recount the ions to make sure it is correctly balanced! :)

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Answer:

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Explanation:

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6 0
3 years ago
How many atoms are in 27.0 grams of aluminum (Al)?
Dmitrij [34]

Answer:

none

Explanation:

4 0
4 years ago
Define the term valence electron and explain how to find the number of valence electrons in family one and family 2.
goblinko [34]
Valence Electron is the outermost electrons, family(Alkali) 1 has 1 valence electrons and family(Alkaline) 2 has 2 valence electrons.

Hope this helps
8 0
4 years ago
Which of the following is used in pencils?
barxatty [35]
Graphite is used

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8 0
4 years ago
Read 2 more answers
A 21.8 g sample of ethanol (C2H5OH) is burned in a bomb calorimeter, according to the following reaction. If the temperature ris
Blababa [14]

<u>Answer:</u> The heat capacity of calorimeter is 15.66J/^oC

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethanol = 21.8 g

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

\text{Moles of ethanol}=\frac{21.8g}{46.07g/mol}=0.473mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = ?

n = number of moles = 0.473 moles

\Delta H_{rxn} = enthalpy change of the reaction  = -1235 kJ/mol = -1235\times 10^3J/mol     (Conversion factor:  1 kJ = 1000 J)

Putting values in above equation, we get:

-1235\times 10^3J/mol=\frac{q}{0.473mol}\\\\q=(-1235\times 10^3J/mol\times 0.473mol)=-584.16\times 10^3J

To calculate the heat capacity of calorimeter, we use the equation:

q=c\Delta T

where,

q = heat absorbed by the calorimeter = 584.16\times 10^3J

c = heat capacity = ?

\Delta T = change in temperature = T_2-T_1=62.3^oC-25^oC=37.3^oC

Putting values in above equation, we get:

584.16\times 10^3J=c\times 37.3^oC\\\\c=\frac{584.16\times 10^3J}{37.3^oC}=15.66J/^oC

Hence, the heat capacity of calorimeter is 15.66J/^oC

4 0
4 years ago
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