All categories

4 years ago

Define the term valence electron and explain how to find the number of valence electrons in family one and family 2.

1 answer:

8 0

Valence Electron is the outermost electrons, family(Alkali) 1 has 1 valence electrons and family(Alkaline) 2 has 2 valence electrons.

Hope this helps

You might be interested in

What types of matter could be separated by physical methods?

rewona [7]

I believe the correct answer to this question is:

“Mixtures”

By definition, mixtures are combination of substances which are not really chemically combined and hence separable by physical means. There are two types of mixtures, homogeneous and heterogeneous, both are also separable by physical means.

<span>This is as opposed to Compounds which are chemically bonded and cannot be separated by physical means.</span>

4 0

4 years ago

2. Which of the following atoms has the smallest atomic radius?

dangina [55]

Answer:

Fluorine.

Explanation:

Fluorine has more protons resulting in a greater nuclear charge, causing a greater attraction for electrons. ... Fluorine has a smaller radius than lithium because of the greater positive charge of the nucleus, pulling electrons and the electron shells in closer.

4 0

3 years ago

An atom that has 13 protons and 15 neutrons is an isotope of the element

kondaur [170]

That would be the element aluminum.

5 0

3 years ago

A student determines the iron(III) content of a solution by first precipitating it as iron(III) hydroxide, and then decomposing

Semmy [17]

Answer:

3.3535 g

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For iron(III) nitrate :

Molarity = 0.404 M

Volume = 52.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 52.0×10⁻³ L

Thus, moles of iron(III) nitrate :

$Moles=0.404 \times {52.0\times 10^{-3}}\ moles$

Moles of iron(III) nitrate = 0.021 moles

1 mole of iron(III) nitrate forms 1 mole of iron(III) hydroxide which further forms 1 mole of iron(III) oxide.

Thus, moles of iron(III) oxide formed from 0.021 moles of iron(III) nitrate = 0.021 moles

Also, molar mass of iron(III) oxide = 159.69 g/mol

So, mass of iron(III) oxide = 0.021 moles × 159.69 g/mol = 3.3535 g

6 0

3 years ago

Find the volume of 10g of gasoline

aleksley [76]

You should divide the mass of gasoline by the density of gasoline.

4 0

4 years ago