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dlinn [17]
3 years ago
10

Please help ASAP pleaseeeeeeeewwe

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

AS = 10\sqrt{41} \\WE = 20\\EN = 25\\Part D = 90 - 10\sqrt{41}

Step-by-step explanation:

AR = 50

AW = WR = EN = 25

RS = 40

RN = NS = WE = 20

AS=\sqrt{(AR)^2+(RS)^2}\\AS=\sqrt{(50)^2+(40)^2} \\AS=\sqrt{2500+1600} \\AS=\sqrt{4100} \\AS=\sqrt{41*100}\\AS = 10\sqrt{41}

AR + RS - AS = 50 + 40 - 10\sqrt{41} \\AR + RS - AS = 90 - 10\sqrt{41}\\AR + RS - AS = 10 (9 - \sqrt{41})

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What is the value of d and w?
Anettt [7]

Answer:

d = 65

w = 55

Step-by-step explanation:

w + 90 + 35 = 180

w + 125 = 180

w = 55

35 + x = 60 (Vertical angle thm)

x = 25

d + x = 90

d + 25 = 90

d = 65

3 0
2 years ago
Dee Dee bought an Apple for $0. 85, a sandwich for $4. 50, and a bottle of water for $1. 50. How much did Dee Dee spend?
OLga [1]

To figure out how much she spent all we have to do is add up $0.85, $4.50 and $1.50

$0.85 + $4.50 + $1.50 = $6.85

Therefore she spent $6.85

Hope this helps

8 0
3 years ago
Read 2 more answers
Alma is finding the measures of the angles in a triangle that have the ratio 1:3:5. circle her mistake and correct it
PolarNik [594]

Answer:

error in summing terms in x

Step-by-step explanation:

x + 3x + 5x = 180 ( collect like terms on left )

9x = 180 ← ( 9x not 8x )

divide both sides by 9

x = 20


3 0
3 years ago
Solve the equation √x-6 +2=6
Dovator [93]

Answer:

x = 22

Step-by-step explanation:

\sqrt{x-6} + 2 = 6 ( subtract 2 from both sides )

\sqrt{x-6} = 4 ( square both sides to clear the radical )

x - 6 = 4² = 16 ( add 6 to both sides )

x = 22

8 0
1 year ago
Find the zeros of y = x2 – 6x – 4 by completing the square.
katrin [286]

Answer:

The solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

Step-by-step explanation:

Given the function

y\:=\:x^2\:-\:6x\:-\:4

substitute y = 0 in the equation to determine the zeros

0\:=\:x^2\:-\:6x\:-\:4

Switch sides

x^2-6x-4=0

Add 4 to both sides

x^2-6x-4+4=0+4

Simplify

x^2-6x=4

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2

x^2-6x+\left(-3\right)^2=13

Apply perfect square formula:  (a-b)² = a²-2ab+b²

\left(x-3\right)^2=13

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-3=\sqrt{13}

Add 3 to both sides

x-3+3=\sqrt{13}+3

Simplify

x=\sqrt{13}+3

now solving

x-3=-\sqrt{13}

Add 3 to both sides

x-3+3=-\sqrt{13}+3

Simplify

x=-\sqrt{13}+3

Thus, the solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

4 0
3 years ago
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