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3 years ago

Please help ASAP pleaseeeeeeeewwe

Mathematics

1 answer:

Arturiano [62]3 years ago

7 0

Answer:

$AS = 10\sqrt{41} \\WE = 20\\EN = 25\\Part D = 90 - 10\sqrt{41}$

Step-by-step explanation:

AR = 50

AW = WR = EN = 25

RS = 40

RN = NS = WE = 20

$AS=\sqrt{(AR)^2+(RS)^2}\\AS=\sqrt{(50)^2+(40)^2} \\AS=\sqrt{2500+1600} \\AS=\sqrt{4100} \\AS=\sqrt{41*100}\\AS = 10\sqrt{41}$

$AR + RS - AS = 50 + 40 - 10\sqrt{41} \\AR + RS - AS = 90 - 10\sqrt{41}\\AR + RS - AS = 10 (9 - \sqrt{41})$

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What happens to the value?

Fiesta28 [93]

Answer:

D.) c is multiplied by 4

Step-by-step explanation:

$c = \dfrac{8a^3}{b}$

If a is doubled, it becomes 2a. If b is doubled, it becomes 2b. Now we replace a with 2a and b with 2b and simplify.

$c = \dfrac{8(2a)^3}{2b}$

$c = \dfrac{8 \times 8a^3}{2b}$

$c = \dfrac{4 \times 8a^3}{b}$

$c = 4 \times \dfrac{8a^3}{b}$

Answer: D.) c is multiplied by 4

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2 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

2 years ago

PLEASE HELP ASAP

Dafna1 [17]

Answer:

Step-by-step explanation:

27.068

28.08

28.15

29.94

6 0

1 year ago

Read 2 more answers

How can you tell that a line segment connecting two points is vertical without graphing the points

pogonyaev

They are intersecting lines if they are not parallel so the other option is that they are intersecting.

4 0

3 years ago

If the price of a gallon of gas was $0.89 in 1984 and was $3.59 in 2014, what was the average rate of change in the price per ga

mylen [45]

Answer:

0.09

Step-by-step explanation:

avg rate of change is: change in y/ change in x

so it´d be 3.59 - 0.89 / 2014 - 1984

= 2.7/ 30

= 0.09

note:

The slope formula and the average rate of change formula are the same, just written a bit different, so you could also use:

y2 - y1 / x2 - x1

8 0

3 years ago