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dlinn [17]
3 years ago
10

Please help ASAP pleaseeeeeeeewwe

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

AS = 10\sqrt{41} \\WE = 20\\EN = 25\\Part D = 90 - 10\sqrt{41}

Step-by-step explanation:

AR = 50

AW = WR = EN = 25

RS = 40

RN = NS = WE = 20

AS=\sqrt{(AR)^2+(RS)^2}\\AS=\sqrt{(50)^2+(40)^2} \\AS=\sqrt{2500+1600} \\AS=\sqrt{4100} \\AS=\sqrt{41*100}\\AS = 10\sqrt{41}

AR + RS - AS = 50 + 40 - 10\sqrt{41} \\AR + RS - AS = 90 - 10\sqrt{41}\\AR + RS - AS = 10 (9 - \sqrt{41})

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In the table what are the donain and range of the function relating the pressure and volume of an idea
7 0
3 years ago
Factorise the following.​
spin [16.1K]

Answer:

x²(9x– 11)(9x + 11)

Step-by-step explanation:

81x⁴ – 121x²

The expression can be factorised as follow:

81x⁴ – 121x²

x² is common to both term. Thus:

81x⁴ – 121x² = x²(81x² – 121)

Recall:

81 = 9²

121 = 11²

Therefore,

x²(81x² – 121) = x²(9²x² – 11²)

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Difference of two squares

x²(9x– 11)(9x + 11)

Therefore,

81x⁴ – 121x² = x²(9x– 11)(9x + 11)

3 0
3 years ago
1) 5.10-2.8.16. 10-1
const2013 [10]

Answer: -2511 (if the periods mean multiplication)

Step-by-step explanation:

I’m not sure whether you’re trying to have the periods be multiplication, but if that’s what they are, this is the answer

5x10-2x8x16x10-1

50-16x160-1

50-2560-1

-2511

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5 0
3 years ago
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vagabundo [1.1K]

We can solve this problem by using the distance formula. The distance formula is: \sqrt{(x_{1}-x)^{2} + (y_{1} - y)^{2}} We can now put in values and solve.

\sqrt{(4-0)^{2} + (-2-10)^{2}}  

\sqrt{16 + 144}

\sqrt{160} 

3 0
3 years ago
Which equation illustrates the identity property of multiplication? (a + bi) × c = (ac + bci) (a + bi) × 0 = 0 (a + bi) × (c + d
labwork [276]

Answer:

(a + bi) \times 1 = (a + bi)

Step-by-step explanation:

The identity property means that whatever you put in is whatever comes out. Notice that if we multiply 1 with any number, we get that number back. So multiplying by 1 is the identity property of multiplication.

8 0
3 years ago
Read 2 more answers
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