Question 3 (2 points)

Please someone help me<br><br> Only the ODD questions please.

Klio2033 [76]

I hope you can read this, and I hope you understand how I did 7. I probably overworked it, and it was possibly a simpler way to get it.

7 0

3 years ago

HELP ALL MY POINTSwhich expression is equivilent to -6(-2/3+2x)

Andrews [41]

Answer:

C

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Jenna and Heidi together have $60. Jenna has $9 more than twice Heidi’s amount. How much money does each have?

Marina86 [1]

Jenna has $43 and Heidi has $17.

Step-by-step explanation:

Total amount = $60

Let,

Amount of Jenna = x

Amount of Heidi = y

According to given statement;

x+y=60 Eqn 1

x=2y+9 Eqn 2

Putting value of Eqn 2 in Eqn 1;

$(2y+9)+y=60\\2y+9+y=60\\3y=60-9\\3y=51$

Dividing both sides by 3,

$\frac{3y}{3}=\frac{51}{3}\\y=17\\$

Putting y=17 in Eqn 2

$x=2(17)+9\\x=34+9\\x=43$

Jenna has $43 and Heidi has $17.

Keywords: linear equations, substitution method

Learn more about substitution method at:

#LearnwithBrainly

4 0

3 years ago

The current process has a mean of 2.50 and a std deviation of 0.05. A new process has been suggested by research. What sample si

Novay_Z [31]

Answer:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got $z_{\alpha/2}=1.96$ , replacing into formula (2) we got:

$n=(\frac{1.96(0.05)}{0.02})^2 =24.01$

So the answer for this case would be n=25 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=0.05$ represent the population standard deviation

n represent the sample size (variable of interest)

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

And on this case we have that ME =0.02 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got $z_{\alpha/2}=1.96$ , replacing into formula (2) we got:

$n=(\frac{1.96(0.05)}{0.02})^2 =24.01$

So the answer for this case would be n=25 rounded up to the nearest integer

7 0

3 years ago

Need help fast please with these 5 questions

vredina [299]

Answer:

1. n = -5

2. n = 6

3. n = 3

4. n = 5

5. n = 0

6 0

3 years ago