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2 years ago

Define variable in mathematics

Mathematics

2 answers:

denis23 [38]2 years ago

8 0

Variable is the unknown value

Shtirlitz [24]2 years ago

6 0

Answer:

A letter to describe a unknown number in an equation

Step-by-step explanation:

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2 r squared + 3s cubed minus r squared + 40 squared minus r squared if R equals -2 s equals -3 and T equals 5

Flura [38]

$2r^2+3s^2-r^2+4t^2-r^2\\\\\text{simplify}\\\\(2r^2-r^2-r^2)+3s^2+4t^2=3s^2+4t^2\\\\s=-3;\ t=5\\\\3(-3)^2+4(5)^2=3(9)+4(25)=27+100=127$

6 0

3 years ago

14. Given: 5x + 4y = 24, x + 7y= 11; Prove: y= 1<br> Statements<br> reasons

Semenov [28]

Answer:

Step-by-step explanation:

We can use the process of elimination as

5x + 4y = 24

5(x + 7y = 11) —> 5x + 35y = 55

5x + 4y = 24

-(5x + 35y = 55)

—————————

-31y = -31

-31y/-31 = -31/-31

y=1

4 0

3 years ago

What is the radius of a circle with an area of 113.04 cubic inches? Use 3.14 for pi.

frosja888 [35]

Answer:

I am deeply sorry for the late answer

but the answer is The answer is

r ≈ 6

Step-by-step explanation:

The answer is r ≈ 6

A ≈ 113.04 cubic in.

this means that

d ≈ 12

and

C ≈ 37.69

Therefore

r ≈ 6

Hope this helped.

6 0

2 years ago

What is the quotient of 2x^(3)+3x^(2)+5x divided by x^(2)+x+1

Anit [1.1K]

<h3><u>Answer</u><u>:</u></h3>

$\large{ \underline{ \boxed{ \green{ \tt{2x + 1 + \frac{2x - 5}{ {x}^{2} + x + 1} }}}}}$

7 0

3 years ago

Find the product.

4vir4ik [10]

Answer :

$6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}$

Step-by-step explanation :

To find the product of

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

$= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)$

we now apply the law of indices

${a}^{m} \times {a}^{n} = {a}^{m+n}$

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

$= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}$

3 0

2 years ago