Answer:
$9$
Step-by-step explanation:
Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.
To find: number that Thea originally entered
Solution:
The final number is $243$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $243$ must be $324$.
As previously the number was squared, so the number before $324$ must be $18$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $18$ must be $81$
As previously the number was squared, so the number before $81$ must be $9$.
Solve for x by simplifying both sides of the equation, then isolating the variable.
x =−60
322 is 7/10 of all the students.
322 / 7 = 46
46 is 1/10 of all the students.
46 × 10 = 460
460 is 10/10 of all the students
There are 460 students in eighth grade.
Just multiply or divide the ratio to get each number to 30.
