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Semenov [28]
3 years ago
9

Please help will give brainliest

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
6 0

Answer:

25 percent ............................

Olegator [25]3 years ago
5 0

Answer:

25% is the answer..............

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Is 3z-1 in standard form?
babunello [35]

Answer:

Yes because

Step-by-step explanation:

Is 3z-1 in standard form?

Yes becausestandard form of a polynomial, the value in the power of the variable such as z in the equation reduces from left to right. Therefore, 3z - 1 is in standard form since the z term comes to the left of the constant term

7 0
2 years ago
In a dance competition, a participant has to score a total of at least 30 points in the first four rounds combined to move on to
77julia77 [94]
<span>So Steward scored 5 for the first round, that will be our constant. There is 3 more rounds for him to score at least 30. at least tells us this is a greater than or equal to 5+3p<30</span>

3 0
3 years ago
If someone average free throw for basketball is 60% how many times in the next 50 tries will she make a free throw. Describe how
Anon25 [30]
So remember that percent means parts out of 100
60%=60/100=6/10
so every 10 throws she makes 6
how many 5 in 50?
50/10=5
answe ris 5
so 5 tens so therefor 5 sixes
5 times 6=30
answer is 30 throws
4 0
3 years ago
The sum of three numbers is 36. The first number is two times the second number, and the second number is
MakcuM [25]

Answer:

o (16, 8, 12)

Step-by-step explanation:

1st number: 8*2 =16

2nd number:12-4=8

3rd number: given

7 0
3 years ago
Read 2 more answers
What is the justification for the first step in proving the formula for factoring the sum of cubes?
Anna11 [10]

Explanation:

The formula isnt correctly written, it should state:

a^3+b^3 = (a+b)(a^2-ab+b^2)

You have to start from (a+b)(a^2-ab+b^2)  and end in a³+b³. On your first step, you need to use the distributive property.

(a+b)(a^2-ab+b^2) = a*(a^2-ab+b^2) + b*(a^2-ab+b^2)

This is equal to

a*a^2-a*(ab) + a*b^2 + b*a^2-b*(ab) + b*b^2 = a^3 - a^2b + ab^2 +ba^2 -b^2a +b^3

Note that the second term, -a²b, is cancelled by the fourth term, ba², and the third term, ab², is cancelled by the fifht term, -b²a. Therefore, the final result is a³+b³, as we wanted to.

5 0
3 years ago
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