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3 years ago

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The ratio of boys to girls in the entire 6th grade is 3 to 2. Given this ratio, which two class compositions are possible?

1 answer:

gtnhenbr [62]3 years ago

7 0

Answer:

<em>There's an infinite number of possible answers because there might be any multiplication of 3 for boys and any multiplication of 2 for girls. So, for example:</em>

<em>There might be 3 boys and 2 girls.</em>

<em>There might be 6 boys and 4 girls.</em>

<em>There might be 9 boys and 6 girls.</em>

<em>There might be 12 boys and 8 girls.</em>

<em>etc...</em>

<em>In each case the ratio stays the same - 3 : 2.</em>

<em>Of course there probably can't be more than a few dozens of people in one class, but theoretically we can raise the numbers up to infinite.</em>

Step-by-step explanation:<em>hope this help.</em>

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Answer:

Approximately 201 squared inches.

Step-by-step explanation:

So, the composite figure is made up of a square and a semi-circle. The square has side lengths of 12 and the semi-circle has a radius of 6.

The total area of the figure would be the area of the square plus the area of the semi-circle. Thus, find the area of each individual figure.

Square:

The area of a square is given by:

$A=l^2$

Where l is the side length.

Substitute 12 for l:

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So the square is 144 square inches.

Semi-circle:

The area of a semi-circle is given by:

$A=\frac{1}{2}\pi r^2$

Substitute 6 for r and 3.14 for π:

$A=\frac{1}{2}(3.14)(6)^2\\ A=56.52$

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Step-by-step explanation:

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