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3 years ago

HELP!! I can't fail. 4 and 5 please!

Mathematics

1 answer:

victus00 [196]3 years ago

6 0

Answer:

4) x = -3 or 8

Step-by-step explanation:

We factories each algebraic expression

4) x² -5x - 24 = 0

x² - 8x + 3x - 24 = 0

(x² - 8x) + (3x - 24) = 0

x(x - 8) + 3(x - 8) = 0

(x + 3)(x - 8) = 0

x + 3 = 0, x = -3

x - 8 = 0, x = 8

x = -3 or 8

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Maggie's brother is three years younger than twice her age. The sum of their ages is 24 how old is maggie?

Vanyuwa [196]

The variable for Maggie will be M and 2x-3 be her younger brothers age (Twice her age). We then would turn this into an algebraic problem. (m+2x -3=24).

3x-3=24, we would add 3 to both sides (-3 and 24). 24 + 3 equals 27, we now have to divide -3x and 27 on both sides, which equals 9. (x=9)

6 0

3 years ago

1. Solve for w in the equation W/5 = 25 A.W = 5 B.W = 125 C. W = 30 D.W = 20

vekshin1

Answer: w = 125

Explanation: Since w is being divided by 5, to solve for w,

multiply both sides of the equation by 5.

On the left side, the 5's will cancel

and on the right side, 25(5) is 125.

So w = 125.

Please do not do this problem in your head.

Show the work that it takes to get w by itself.

3 0

3 years ago

Solve by elimination

inna [77]

2x - 2y = -4
-3x -3y = 0
_____________________
-1x - 5y = -4

4 0

3 years ago

Read 2 more answers

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .