If 
, all angles would be equal, resulting in similar triangles. So B is right
Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:3x^2-5x+2=0
Step-by-step explanation:
Format of a quadratic equation= ax^2 +bx+c
Let x=1 and 2/3
When x=1
x-1=0.......(1)
When x=2/3
x-2/3=0.........(2)
Compare the equations
(x-1)(x-2/3)=0
x^2-2/3x-x+2/3=0
x^2-5/3x+2/3=0
Multiply all terms by 3
3x^2-5x+2=0
Answer:
Part A:
Formula for circumference: C = diameter x pi
=> pi = C/diameter
=> pi(A) = 12.56/4 =3.14
=> pi(B) = 6.28/2 = 3.14
Part B:
Formula for area: A = radius^2 x pi = (diameter/2)^2 x pi
=> pi = A/(diameter/2)^2
=> pi(A) = 12.56/(4/2)^2 = 12.56/4 = 3.14
=> pi(B) = 3.14/(2/2)^2 = 3.14/1 = 3.14
Part C:
pi(A) = pi(B) = 3.14 in both ways of calculation derived from circumstance and area.
=> pi is a constant value: 3.14
<h3>
<u>Answer</u><u>:</u></h3>
Perimeter → 25cm
Area → 25.5cm²
<h3><u>Explanation</u>:</h3>
