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stepladder [879]
2 years ago
5

Two car dealers in town are offering different sales on the same model of car. Sandra can buy the car from Al's Cars, which norm

ally sells the car for $11,000 but will offer a 15% discount. Or she can buy the car from CarWorld, where the car sells for $12,500 and the dealership offers a 20% discount.
A. What is the price of the car at each dealership after the markdown?

B. How much will sandra save by going to the correct car dealer?


PLEASE HELP!!!​
Mathematics
1 answer:
OleMash [197]2 years ago
5 0
A. AI cars $9350 and CarWorld $10000
B. She will save $1650 going to AI’s dealership
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A company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that
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Probability that the company wins project A or project B is 0.50.

Step-by-step explanation:

We are given that a company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that the company wins project B is 0.25.

Also, Winning project A and winning project B are independent events.

Let the Probability of winning project A = P(A) = 0.40

            Probability of winning project B = P(B) = 0.25

<u>Now, as we know that ;</u>

Probability that the company wins project A or project B = P(A \bigcup B)

              P(A \bigcup B) = P(A) + P(B) -  P(A \bigcap B)

So, we have to find the value of Probability of winning project A and B, i.e;

P(A \bigcap B)

<em>Since, we are given that Winning project A and winning project B are independent events which means when this condition is given then;</em>

                    P(A \bigcap B) = P(A) \times P(B)

                                    = 0.40 \times 0.25 = 0.10

Now, Probability that the company wins project A or project B is given by;

                 P(A \bigcup B) = P(A) + P(B) -  P(A \bigcap B)  

                                  = 0.40 + 0.25 - 0.10

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Hence, probability that the company wins project A or project B is 0.50.

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