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kozerog [31]
2 years ago
5

Which three quantities can be used to calculate acceleration?

Physics
1 answer:
ikadub [295]2 years ago
5 0
The correct option will be
D. Time, initial velocity and final velocity
The Formula can be written as,
Acceleration=Final velocity-Initial Velocity/Time
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A girl stands on the edge of a merry-go-round of radius 1.71 m. If the merry go round uniformly accerlerates from rest to 20 rpm
Mashutka [201]

Answer:

a = 0.53 m/s^2

Explanation:

initially the merry go round is at rest

after 6.73 s the merry go round will accelerates to 20 rpm

so final angular speed is given as

\omega = 2\pi f

\omega = 2\pi ( \frac{20}{60})

\omega = 2.10 rad/s

so final tangential speed is given as

v = r\omega

v = 1.71 (2.10) = 3.58 m/s

now average acceleration of the girl is given as

a = \frac{v_f - v_i}{\Delta t}

a = \frac{3.58 - 0}{6.73}

a = 0.53 m/s^2

8 0
3 years ago
The distance between two successive peaks on adjacent waves is its
yKpoI14uk [10]

Answer:

Wavelength

Explanation:

Wavelength is the distance between two corresponding consecutive phases of a waveform. It is usually represented by λ in the mathematical expressions.

A continuous propagating wave repeats its wavelength over the distance.

A wave has crest and trough with respect to time and space.

Wave is defined as a disturbance of any parameter repeated in a cyclic manner over the given time.

3 0
3 years ago
At what speed, as a fraction of c , is a particle's total energy twice its rest energy
WINSTONCH [101]
The rest energy of a particle is
E_0=m_0 c^2
where m_0 is the rest mass of the particle and c is the speed of light.

The total energy of a relativistic particle is
E=mc^2 =  \frac{m_0 c^2}{ \sqrt{1- \frac{v^2}{c^2} } }
where v is the speed of the particle.

We want the total energy of the particle to be twice its rest energy, so that
E=2E_0
which means:
\frac{m_0c^2}{ \sqrt{1- \frac{v^2}{c^2} } }=2m_0 c^2
\frac{1}{ \sqrt{1- \frac{v^2}{c^2} } }=2
From which we find the ratio between the speed of the particle v and the speed of light c:
\frac{v}{c}=  \sqrt{1- (\frac{1}{2})^2 }  =0.87
So, the particle should travel at 0.87c in order to have its total energy equal to twice its rest energy.
3 0
3 years ago
The two properties of an electron that cannot be known exactly at the same time are the ____________________.
enyata [817]
Position and momentum.

This is Heisenberg's Uncertainty Principle:
Δx Δp ≥ h ÷ 4π,   where Δx is the change in position, Δp is the change in momentum, and h is Planck's Constant.
6 0
3 years ago
A wheel decelerates from 13.5 rad s−1 to 6.0 rad s−1 in 7 s. Calculate the angular displacement​
Igoryamba

Answer:

<em>Angular displacement=68.25 rad</em>

Explanation:

<u>Circular Motion</u>

If the angular speed varies from ωo to ωf in a time t, then the angular acceleration is given by:

\displaystyle \alpha=\frac{\omega_f-\omega_o}{t}

The angular displacement is given by:

\displaystyle \theta=\omega_o.t+\frac{\alpha.t^2}{2}

The wheel decelerates from ωo=13.5 rad/s to ωf=6 rad/s in t=7 s, thus:

\displaystyle \alpha=\frac{6-13.5}{7}

\displaystyle \alpha=\frac{-7.5}{7}

\displaystyle \alpha=-1.071 \ rad/s^2

Thus, the angular displacement is:

\displaystyle \theta=13.5*7+\frac{-1.071*7^2}{2}

\displaystyle \theta=94.5-26.25

\boxed{\displaystyle \theta=68.25\ rad}

Angular displacement=68.25 rad

3 0
3 years ago
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