Answer:
D) the second at the doorknob
Explanation:
The torque exerted by a force is given by:
where
F is the magnitude of the force
d is the distance between the point of application of the force and the centre of rotation
is the angle between the direction of the force and d
In this problem, we have:
- Two forces of equal magnitude F
- Both forces are perpendicular to the door, so 
- The first force is exerted at the midpoint of the door, while the 2nd force is applied at the doorknob. This means that d is the larger for the 2nd force
--> therefore, the 2nd force exerts a greater torque
Answer:
Second Trial satisfy principle of conservation of momentum
Explanation:
Given mass of ball A and ball B 
Let mass of ball 
and 
Final velocity of ball 
Final velocity of ball 
initial velocity of ball 
Initial velocity of ball 
Momentum after collision 
Momentum before collision 
Conservation of momentum in a closed system states that, moment before collision should be equal to moment after collision.
Now, 
Plugging each trial in this equation we get,
First Trial
momentum before collision 
moment after collision
Second Trial
moment before collision 
moment after collision
Third Trial
momentum before collision moment after collision
Fourth Trial
momentum before collision moment after collision
We can see only Trial- 2 shows the conservation of momentum in a closed system.
A)
At time = .003 hr
B)
90* (3*10^-3) = .27km
C)
.005 hr
D)
Car A = 150 * (.005) = .75km
Car B = (90 * (.005) = .45 km
E)
Car A = 150 * (0.008) = 1.2 km
Car B = 90 * (0.008) = 0.72 km
Car A is ahead
Answer:
Pure Food and Drug Act of 1906
Explanation:
The Pure Food and Drug Act of 1906 prohibited the sale of misbranded or adulterated food and drugs in interstate commerce and laid a foundation for the nation's first consumer protection agency, the Food and Drug Administration
Answer:
3272.4 Hz
Explanation:
L = 31 mH
XL = 637 ohm
XL = 2 π f L
f = XL / (2 π L)
f = 637 / ( 2 x 3.14 x 31 x 10^-3)
f = 3272.4 Hz
