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Luba_88 [7]
3 years ago
10

Which is a characteristic property of acids? a. They turn blue litmus paper red. b. They turn red litmus paper blue. c. They tas

te bitter. d. They do not react with metals.
Physics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0
The answer is B they turn litmus paper red
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You carry a 5 kg sack of potatoes across the store for 5 minutes, and you wait in line holding it for 30 seconds before you get
ludmilkaskok [199]

Answer:

The only work done is when the person lifts the sack over a distance, W = 78.48 [N]

Explanation:

We have to remember the definition of work, which tells us that work is the result of a force by a distance, we must apply this concept in each of the movements of the person in the problem described.

W = F * d

where:

F = force [N]

d = distance [m]

The force is given by the producto of the mass by the gravity.

F = 5 * 9.81 = 49.05 [N]

W = 49.05 * 1.6 = 78.48 [N]

3 0
3 years ago
As you sit in a chair, in what direction (or directions) do you exert an action force?
enyata [817]
As we sit in a chair, Action force will be only in one direction and that direction would be downward only.

In short, Your Answer would be Option A

Hope this helps!
5 0
3 years ago
Read 2 more answers
Draw a distance over time graph of a dog that is tied to a 4 foot rope and travels in 1 complete circle
Soloha48 [4]
I think this is the answer. I hope you can understand.

6 0
3 years ago
Which of the following is NOT an indicator of a physical change?
S_A_V [24]

Answer:

1.  C.  The change is easily reversible

2. A.  a physical change

Explanation:

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8 0
3 years ago
astronauts in space cannot weigh themselves by standing on a bathroom scale. Instead, they determine their mass by oscillating o
devlian [24]

Answer:

The right answer is:

(a) 63.83 kg

(b) 0.725 m/s

Explanation:

The given query seems to be incomplete. Below is the attachment of the full question is attached.

The given values are:

T = 3 sec

k = 280 N/m

(a)

The mass of the string will be:

⇒ T=2 \pi\sqrt{\frac{m}{k} }

or,

⇒ m=\frac{k T^2}{4 \pi^2}

On substituting the values, we get

⇒     =\frac{280\times (3)^2}{4 \pi^2}

⇒     =\frac{280\times 9}{4\times (3.14)^2}

⇒     =68.83 \ kg

(b)

The speed of the string will be:

⇒  \frac{1}{2}k(0.4)^2=\frac{1}{2}k(0.2)^2+\frac{1}{2}mv^2

then,

⇒             v=\sqrt{\frac{k((0.4)^2-(0.2)^2)}{m} }

On substituting the values, we get

⇒                =\sqrt{\frac{280\times ((0.4)^2-(0.2)^2)}{63.83} }

⇒                =\sqrt{\frac{280(0.16-0.04)}{63.83} }

⇒                =\sqrt{\frac{280\times 0.12}{63.83} }

⇒                =0.725 \ m/s

4 0
3 years ago
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