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german
2 years ago
5

Add and Subtract the fractions below: 1/3 and 1/4

Mathematics
1 answer:
Alex2 years ago
6 0

Addition Answer: 1/3 + 1/4 = 4/12 + 3/12 = 7/12

Subtraction Answer: 1/3 - 1/4 = 4/12 - 3/12 = 1/12

Step-by-step explanation:

Basically, find the greatest common multiple of 3 and 4.  Once you do this, then you can multiply across and solve any fraction problem!

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Determine the number of solutions for the linear equation shown below?<br> 4(3x+8)−9=2(6x−8)−15
natta225 [31]

Answer:

0 = -54

Step-by-step explanation:

4(3x + 8) − 9 = 2(6x − 8) − 15

12x + 32 - 9 = 12x - 16 - 15

12x + 23 = 12x - 31

12x = 12x - 54

0 = -54

No solutions.

Best of Luck!

5 0
2 years ago
HELP QUICKLY PLEASE!!!
storchak [24]

9,11,13,20

20 -9 = 11

Range: 11 so its not 17

11 + 13 = 24

24/2 = 12

Median: 12 so its not 10

9+ 11 + 13 + 20 = 53

53/4= 13.25

Mean: 13.25 so its not 12

IQR: 6.5 so its not 7 or 12

4 0
2 years ago
Pls help <br><br> Evaluate. [120 + (12 ÷ 3 • 30)] ÷ 20 + 102
sleet_krkn [62]
The answer is 114. Here’s what I did.

4 0
2 years ago
April lost 5 pounds in her first week of college. Over the next three weeks she lost 3 pounds, gained 2 pounds, and then lost 1
Doss [256]

Change in April's weight is -7

<em><u>Solution:</u></em>

Let the initial weight be "x"

April lost 5 pounds in her first week of college

First week = lost 5 pounds

Therefore, x - 5

Over the next three weeks she lost 3 pounds, gained 2 pounds, and then lost 1 pound

<em><u>Next three week:</u></em>

Lost 3 pound

Gained 2 pound

Lost 1 pound

<em><u>Therefore, weight after 4 weeks is given as:</u></em>

x - 5 - 3 + 2 - 1 = x -7

After 4 week, the weight is x - 7

<em><u>The change in April weight is given as:</u></em>

Weight after 4 week - initial weight = x - 7 - x = -7

Thus change in April's weight is -7 (Negative sign represents loss in weight )

4 0
3 years ago
What is <br><img src="https://tex.z-dn.net/?f=8.4%20-%204.2" id="TexFormula1" title="8.4 - 4.2" alt="8.4 - 4.2" align="absmiddle
STALIN [3.7K]

Answer:

4.2

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\space\space&8&.&4\\ -&4&.&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-2=2

\frac{\begin{matrix}\space\space&8&.&\textbf{4}\\ -&4&.&\textbf{2}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}\end{matrix}}

\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}

\frac{\begin{matrix}\space\space&8&\textbf{.}&4\\ -&4&\textbf{.}&2\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{.}&2\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:8-4=4

\frac{\begin{matrix}\space\space&\textbf{8}&.&4\\ -&\textbf{4}&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&.&2\end{matrix}}

=4.2

3 0
2 years ago
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