Answer:
9 quarters and 26 dimes
Step-by-step explanation:
your welcome :)
The position function of a particle is given by:
The velocity function is the derivative of the position:
The particle will be at rest when the velocity is 0, thus we solve the equation:
The coefficients of this equation are: a = 2, b = -9, c = -18
Solve by using the formula:
![t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Substituting:
![\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81-4%282%29%28-18%29%7D%7D%7B2%282%29%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B81%2B144%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm%5Csqrt%5B%5D%7B225%7D%7D%7B4%7D%20%5C%5C%20t%3D%5Cfrac%7B9%5Cpm15%7D%7B4%7D%20%5Cend%7Bgathered%7D)
We have two possible answers:
We only accept the positive answer because the time cannot be negative.
Now calculate the position for t = 6:
Answer:
x=y^2-2
Step-by-step explanation:
This graph, is a parabola that opens to the right.
To answer this question, we just use the vertex form of a sideways parabola- x=a(y-k)^2+h.
In this case, the vertex is (-2, 0), and our value of a is 1, since it opens to the right.
This gives us: x=1(y-0)^2+(-2)
Which simplifies to: x=y^2-2.
Also, the answer to the previous two questions are wrong.
The D value (Domain) is actually [2, ∞)
The R value (Range) is actually "All real numbers" (-∞, ∞)
Let me know if this helps!
Perimeter = 2(length + width)
p = 2(10'5" + 9'8")
p = 2(19'13")
p = 38'26"
26" = 2'4"
So...
38' + 2'4" = 40' 4" for the perim,eter
I believe it's it's d
Sorry if I'm wrong I'm mr lemonade
