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V125BC [204]
3 years ago
9

Erin was completing the square of the quadratic function in order to find the extreme value. What is the next step in the proces

s, and what is the extreme value?
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
7 0

Step-by-step explanation:

ax^2+bx+c=0

a=leading term

ok so if the leading term is positive then opens up and has a <u>min</u>

if leading term is negative then opens down and has a <u>max</u>

leading term is positive

1x^2+8x

it has a min

to complete the square, move c aside take 1/2 of b and square it

b=8

8/2=4

4^2=16

now add that to both sides

x^2+8x+16+6=0+16

factor perfect square

(x+4)^2+6=16

subtract 6

(x+4)^2=10

subtract 10

(x+4)^2-10=0

vertex aka min or max is (h,k) when ou have

y=a(x-h)+k

h=-4

k=-10

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Use a quadratic equation to find two numbers whose sum is 5 and whose product is ­- 24.
prisoha [69]
Hello 
if m s : sum   and p : <span> product
the </span><span> quadratic equation is : x²-sx+p=0
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8 0
3 years ago
Kenny reads 4/9 page in 3/5 min. what is Kenny's unit rate? <br><br> Step by step.
il63 [147K]

Answer:

The unit rate is \frac{27}{20}\text{ page/minute}

Step-by-step explanation:

Given : Kenny reads \frac{4}{9} page in \frac{3}{5} min.

To find : What is Kenny's unit rate?

Solution :

Kenny reads \frac{4}{9} page in \frac{3}{5} minute

This can be written as,

\frac{4}{9}\text{ page}=\frac{3}{5}\text{ minute}

Divide both side by \frac{9}{4}

\frac{4}{9}\times \frac{9}{4}\text{ page}=\frac{3}{5}\times \frac{9}{4}\text{ minute}

1\text{ page}=\frac{27}{20}\text{ minute}

The unit rate is \frac{27}{20}\text{ page/minute}

4 0
3 years ago
A = {1, 3, 5, 7, 9} B = {2, 4, 6, 8, 10} C = {1, 5, 6, 7, 9} A ∩ (B ∪ C) =
vovikov84 [41]
A = {1, 3, 5, 7, 9}
B = {2, 4, 6, 8, 10}
C = {1, 5, 6, 7, 9}

(B ∪ C) = {1, 2, 4, 5, 6, 7, 8, 9, 10}
so
A ∩ (B ∪ C) = {1, 5, 7 , 9}
6 0
3 years ago
You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp
Katena32 [7]
Let's move like a crab, backwards some.

after 2 years?

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after 3 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$1000\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &3&#10;\end{cases}&#10;\\\\\\&#10;A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3

is that enough to pay the $1100?


now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000   <---- standard form.
8 0
3 years ago
I dont get this question, anyone help me please
prisoha [69]
Its a line plot, for every number that is listed put a mark above the number on the number line. So if there was 3 6's, on the number line above the 6, put 3 marks like dots or x's to represent the amount of 6.
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4 0
3 years ago
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