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alex41 [277]
3 years ago
14

What is the area acellus help plz

Mathematics
2 answers:
trapecia [35]3 years ago
7 0

Answer:

This unit discusses areas of paralelograms, triangles, trapezoids, rhombuses, kites, and regular polygons.

Step-by-step explanation:

svet-max [94.6K]3 years ago
5 0
The area is 97 because when you do the mathematical equation thats the answer
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30 PTS BRAINLIEST FOR BEST ANSWER The graph of f(x) = (0.5)^x is replaced by the graph of g(x) = (0.5)^x − k. If g(x) is obtaine
pogonyaev
The graph of f(x) = (0.5)^x is replaced by the graph of g(x) = (0.5)^x − k. If g(x) is obtained by shifting f(x) down by 2 units, the value of k is 2 because g(x)=(.5)x-2. g(x) is f(x) without the "shift" and it said the shift was 2 units, so k is 2
5 0
4 years ago
Solve. Please show your work
Sphinxa [80]

Answer:

128

Step-by-step explanation:

8^2√2^2

64√2^2              rewrite √2^2 as 2

64*2

=128

5 0
3 years ago
How many 1/12 parts are in 9/12
DENIUS [597]

Answer:

Nine

Step-by-step explanation:

Given the following question:

12/12 = 12 parts or 1 whole unit
1/12 = 1 part of that unit
9/12 = 9 parts of that unit

If 12 parts are needed to create one whole unit or 12/12, that means they're 9, 1/12 parts in the fraction 9/12.

Your answer is "nine."

Hope this helps.

3 0
3 years ago
An English professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below the
klio [65]

Solution :

The test is distributed normally with mean of 72.8 and the standard deviation of 7.3

Finding numerical limits for the D grade.

D grade : Scores below the top 80% and above the bottom 10%.

Let the bottom limit for D grade be $D_1$ and the top limit for D grade be $D_2$.

First find the bottom numerical limit for a D grade is :

$P(X

$P(X\leq D_1)= 0.10$

$P\left(\frac{X-\mu}{\sigma} \leq \frac{D_1-\mu}{\sigma}\right) = 0.10$

$P\left(Z \leq \frac{D_1-72.8}{7.3}\right) = 0.10$    ..........(1)

From (1)

$\frac{D_1 - 72.8}{7.3} = -1.28$

$D_1 = -1.28(7.3)+72.8$

      = 63.45

       ≈ 64

Now the top numerical limit for D grade :

$P(X>D_2)= 0.80$

$1-P(X\leq D_2)= 0.80$

$P(X\leq D_2)= 1-0.80$

$P(X\leq D_2)= 0.20$

$P\left(\frac{X-\mu}{\sigma} \leq \frac{D_2-\mu}{\sigma}\right) = 0.20$

$P\left(Z \leq \frac{D_2-72.8}{7.3}\right) = 0.20$    ..........(2)

From (2)

$\frac{D_2- 72.8}{7.3} = -0.84$

$D_12= -0.84(7.3)+72.8$

      = 66.668

       ≈ 67

Therefore, the numerical limit for a D grade is 64 to 67.

7 0
3 years ago
PLEASE HELP 50 POINTS
natima [27]

Answer:

C. 1/3<b<3/2

D. 1/6<x<2

Step-by-step explanation:

Hope this helps

3 0
3 years ago
Read 2 more answers
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