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2 years ago

6

The original blueprint of a rectangular concrete patio has a scale of 2 inches = 3 feet. The blueprints dimensions are 14 in by

12 in. What is the actual area of the rectangular patio?

1 answer:

tester [92]2 years ago

5 0

Answer:

3+2 14+12 i guess

Step-by-step explanation:

You might be interested in

Find the Area of the quadrilateral. Please help

Nikitich [7]

Answer:

18 ft^2

Step-by-step explanation:

This quadrilateral is a parallelogram.

Area = base × height

= 6 × 3

= 18 ft^2

6 0

3 years ago

11 pints is how may quarts

yaroslaw [1]

2 pints per quart. Therefore, 11 pints/2 pints per quart = 5.5 quarts.

If you find my answer helpful, please brainliest me!

8 0

3 years ago

FIRST ONE TO GIVE ME A CORRECT ANWSER GETS BRAINLIEST

klio [65]

Answer:

multiply by 5, t = 14.5

Step-by-step explanation:

t/5 = 2.9 (multiply each side by 5)

t = 14.5

3 0

3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago

A ball is floating partially submerged in a liquid. Which quantity equals the buoyant force acting on the ball? mass of the ball

REY [17]

For something to float the buoyant force ( force pushing up on the object to keep it floating) needs to equal the weight of the object

the answer would be: <span>weight of the ball</span>

6 0

3 years ago