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nlexa [21]
2 years ago
6

The original blueprint of a rectangular concrete patio has a scale of 2 inches = 3 feet. The blueprints dimensions are 14 in by

12 in. What is the actual area of the rectangular patio?
Mathematics
1 answer:
tester [92]2 years ago
5 0

Answer:

3+2     14+12 i guess

Step-by-step explanation:

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Find the Area of the quadrilateral. Please help
Nikitich [7]

Answer:

18 ft^2

Step-by-step explanation:

This quadrilateral is a parallelogram.

Area = base × height

= 6 × 3

= 18 ft^2

6 0
3 years ago
11 pints is how may quarts
yaroslaw [1]

2 pints per quart. Therefore, 11 pints/2 pints per quart = 5.5 quarts.

If you find my answer helpful, please brainliest me!

8 0
3 years ago
FIRST ONE TO GIVE ME A CORRECT ANWSER GETS BRAINLIEST
klio [65]

Answer:

multiply by 5, t = 14.5

Step-by-step explanation:

t/5 = 2.9 (multiply each side by 5)

t = 14.5

3 0
3 years ago
find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

8 0
2 years ago
A ball is floating partially submerged in a liquid. Which quantity equals the buoyant force acting on the ball? mass of the ball
REY [17]
For something to float the buoyant force ( force pushing up on the object to keep it floating) needs to equal the weight of the object

 the answer would be: <span>weight of the ball</span>



6 0
3 years ago
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