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ExtremeBDS [4]
3 years ago
6

. A restaurant charges a $100 setup fee, plus $15 per guest, to host a private party. The table

Mathematics
2 answers:
Aleks [24]3 years ago
5 0

Answer:

the CORRECT answer is $775

Step-by-step explanation:

multiply the guests by the amount for each then add the setup price.

45 x 15 = 675 + 100 = $775

guests=45

$ per guest=$15

setup price=$100

netineya [11]3 years ago
3 0

Answer:

42

Step-by-step explanation:

i said so

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If x=-7 is a root of the equation x^2+kx+49=0, then k=​
aleksley [76]

Answer:

k=14

Step-by-step explanation:

Given:

x^{2}+kx+49 = 0

x = -7

Substitution can be used to find the value of k:

(-7)^{2}+(-7)k+49 = 0

49-7k+49 = 0

98 -7k = 0

k = 14

Hope this helps :)

8 0
3 years ago
Let A and B be two events in a sample space S such that
klasskru [66]
P(A|B)<span>P(A intersect B) = 0.2 = P( B intersect A)

</span>A) P(A intersect B) = <span>P(A|B)*P(B)
Replacing the known vallues:
0.2=</span><span>P(A|B)*0.5
Solving for </span><span>P(A|B):
0.2/0.5=</span><span>P(A|B)*0.5/0.5
0.4=</span><span>P(A|B)
</span><span>P(A|B)=0.4
</span>
B) P(B intersect A) = P(B|A)*P(A)
Replacing the known vallues:
0.2=P(B|A)*0.6
Solving for P(B|A):
0.2/0.6=P(B|A)*0.6/0.6
2/6=P(B|A)
1/3=P(B|A)
P(B|A)=1/3
5 0
3 years ago
A water tank already contained 24 gallons of water before a pump was switched to fill it. The pump started at 10:00 am and by 10
grigory [225]

Answer:

The equation to represent  the amount of water that the tank contains (W) after the pump was working for T hours can be given as:

W=32T+24

Step-by-step explanation:

Given:

Water tank initially contained = 24 gallons of water

The pump to fill the tank was switched to fill it.

From 10:00 AM to 10:30 AM the tank contained 40 gallons of water.

By 1:00 PM the tank contained 120 gallons of water.

To write an equation  which will tell the amount of water that the tank contains (W) after the pump was working for T hours

Solution:

Initially, gallons of water in tank = 24

From 10:00 AM to 10:30 AM the tank had 40 gallons of water.

Thus, in half an hour the pump filled = 40-24 = 16 gallons

Using unitary method:

If in \frac{1}{2} of an hour water filled = 16 gallons

So, in 1 hour the water filled will be = 16\times 2 = 32 gallons

In 3 hours the water filled will be = 32\times 3 = 96 gallons

Thus, by 1:00 PM the water in the tank will be = 96+24 = 120 gallons

This confirms the data given for 1:00 PM.

This shows that the rate at  which the pump fills the tank is 32 gallons of water per hour.

The equation to represent  the amount of water that the tank contains (W) after the pump was working for T hours can be given as:

W=32T+24

4 0
3 years ago
-54 - 7r = -5(-2 - 5r)
makkiz [27]
-54-7r=10+25r
-7r-25r=10+54
-32r=64
r=64/-32
r=-2
3 0
3 years ago
I need help fast. It is number 14
Anon25 [30]

The percent is 145. That should be your answer

5 0
3 years ago
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