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3 years ago

. A restaurant charges a $100 setup fee, plus $15 per guest, to host a private party. The table

Mathematics

2 answers:

Aleks [24]3 years ago

5 0

Answer:

the CORRECT answer is $775

Step-by-step explanation:

multiply the guests by the amount for each then add the setup price.

45 x 15 = 675 + 100 = $775

guests=45

$ per guest=$15

setup price=$100

netineya [11]3 years ago

3 0

Answer:

Step-by-step explanation:

i said so

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Factor.<br> 28 - 4u<br> I don’t know how to factor 28-4u so if anyone can help thank you

Sedaia [141]

Answer: 4(7-u)

Step-by-step explanation:

In order to factor, you have to find the GCF (Greatest Common Factor)

28:1, 28, 2, 14, 4, 7

4:1, 4, 2

The greatest common factor here is 4.

You can factor out 4 from this equation, therefore making it 4(7-u)

3 0

3 years ago

We are planning a reception for our daughter. The hall that we are renting charges a $50 cleanup fee. In

Step2247 [10]

Answer:

The answer is 235

Step-by-step explanation:

it's just basic long divistion.

6 0

3 years ago

You are saving for a bicycle that costs $120. You Deposit $75 in an account that earns compounded annually. The Expression 75(1+

dezoksy [38]

A. Expanding the given expression, you have
balance = 75r^2 +150r +75

B. For r=0.10, the balance after 2 years is 75*1.1^2 = 90.75

C. The difference between $120 and 90.75 is $29.25. You need $29.25 more to buy the bicycle.

8 0

3 years ago

A rectangle has a length of 12 yards less than 3 times its width. If the area of the rectangle is 135 square yards, find the len

Aleonysh [2.5K]

Answer:

The length is 15 yards

Step-by-step explanation:

Given

Represent the width with W and length with L: So

$Area = 135yd^2$

$L=3W - 12$

Required

Determine the length of the rectangle:

Area is calculated as thus:

$Area = L * W$

Substitute 3W - 12 for L and 135 for Area

$135= (3W - 12) * W$

$135= 3W^2 - 12W$

Reorder:

$3W^2 - 12W - 135= 0$

Divide through by 3

$W^2 - 4W - 45 = 0$

Expand:

$W^2 - 9W + 5W - 45 = 0$

$W(W - 9) + 5(W - 9) = 0$

$(W + 5)(W-9) = 0$

$W + 5 = 0$ or $W - 9 = 0$

$W = -5$ or $W = 9$

But width can't be negative

So:

$W = 9$

Recall that: $L=3W - 12$

$L = 3 * 9 - 12$

$L = 15$

<em>Hence, the length 15 yards</em>

4 0

3 years ago

If 2k, 5k-1 and 6k+2 are the first 3 terms of an arithmetic sequence, find k and the 8th term

Klio2033 [76]

Answer:

see explanation

Step-by-step explanation:

The common difference d of an arithmetic sequence is

d = $a_{2}$ - $a_{1}$ = $a_{3}$ - $a_{2}$

Substitute in values and solve for k, that is

5k - 1 - 2k = 6k + 2 - (5k - 1)

3k - 1 = 6k + 2 - 5k + 1

3k - 1 = k + 3 ( subtract k from both sides )

2k - 1 = 3 ( add 1 to both sides )

2k = 4 ⇒ k = 2

--------------------------------------------------------

The n th term of an arithmetic sequence is

$a_{n}$ = $a_{1}$ + (n - 1)d

$a_{1}$ = 2k = 2 × 2 = 4 and

d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5

Hence

$a_{8}$ = 4 + (7 × 5) = 4 + 35 = 39

4 0

3 years ago