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3 years ago

The radius of a circle is 2 millimeters. What is the circle's area?

Mathematics

1 answer:

mote1985 [20]3 years ago

6 0

Answer:

12.56 mm²

Step-by-step explanation:

$A=\pi r^{2}$

Plug the given values into the area equation

$A=3.14*2^{2}\\A=3.14*4\\A=12.56$

Therefore, the area of the circle is 12.56 mm².

I hope this helps!

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Figure ABCD is transformed to figure A′B′C′D′:

sasho [114]

Your answer would be...

<span>Angle C prime D prime A prime.

This is because this is the angle after the transformation, and the angle did not change.
</span>

4 0

3 years ago

I have been stuck on this forever plz help <br> What is the surface area of this cylinder

Andrei [34K]

Answer:

1865.16 m^2

Step-by-step explanation:

first let 's find radius of a circle

radius=diameter/2

=18/2

=9 m

area of a cylinder=2πrh+2πr2

=2*3.14*9*24 + 2*3.14*(9)^2

=1356.48 + 2*3.14*81

=1356.48 + 508.68

=1865.16 m^2

6 0

2 years ago

Read 2 more answers

Use the discriminant to determine what type of roots the equations will have, and categorize the equations according to their ro

topjm [15]

Step-by-step explanation:

The discriminant of the quadratic equation $ax^2+bx+c=0$ :

$\Delta=b^2-4ac$

If Δ < 0, then the equation has two complex roots $x=\dfrac{-b\pm\sqrt\Delta}{2a}$

If Δ = 0, then the equation has one repeated root $x=\dfrac{-b}{2a}[/tex If Δ > 0, then the equation has two discint roots [tex]x=\dfrac{-b\pm\sqrt\Delta}{2a}$

$1.\ x^2-4x+2=0\\\\a=1,\ b=-4,\ c=2\\\\\Delta=(-4)^2-4(1)(2)=16-8=8>0,\ \bold{two\ distinct\ roots}\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=2\sqrt2\\\\x=\dfrac{-(-4)\pm2\sqrt2}{2(1)}=\dfrac{4\pm2\sqrt2}{2}=2\pm\sqrt2\\\\==============================\\\\2.\ 5x^2-2x+3=0\\\\a=5,\ b=-2,\ c=3\\\\\Delta=(-2)^2-4(5)(3)=4-60=-56$

$3.\ 2x^2+x-6=0\\\\a=2,\ b=1,\ c=-6\\\\\Delta=1^2-4(2)(-6)=1+48=49>0,\ \bold{two\ distinct\ roots}\\\sqrt\Delta=\sqrt{49}=7\\\\x=\dfrac{-1\pm7}{(2)(2)}\\\\x_1=\dfrac{-8}{4}=-2,\ x_2=\dfrac{6}{4}=\dfrac{3}{2}\\\\==============================\\\\4.\ 13x^2-4=0\qquad\text{add 4 to both sides}\\\\13x^2=4\qquad\text{divide both sides by 13}\\\\x^2=\dfrac{4}{13}\to x=\pm\sqrt{\dfrac{4}{13}},\ \bold{two\ distinct\ roots}\\\\==============================$

$5.\ x^2-6x+16=0\\\\a=1,\ b=-6,\ c=16\\\\\Delta=(-6)^2-4(1)(16)=36-64=-28$

$7.\ 4x^2+11=0\qquad\text{subtract 11 from both sides}\\\\4x^2=-11\qquad\text{divide both sides by 4}\\\\x^2=-\dfrac{11}{4}\to x=\pm\sqrt{-\dfrac{11}{4}}\\\\x=\pm\dfrac{\sqrt{11}}{2}\ i,\ \bold{two\ complex\ roots}$

6 0

3 years ago

Read 2 more answers

What single decimal multiplier would you use to increase by 7% followed by a 4% decrease?

Nostrana [21]

Answer: To increase an amount by 7%, you would want to use 1.07 as the multiplier. To decrease it, you would use 0.93

Step-by-step explanation:

4 0

3 years ago

Find the standard deviation for the set of data. (17,26,28,9,30, 29,6,21,23}

gogolik [260]

Using it's concept, the standard deviation for the given data-set is of 8.22.

<h3>What are the mean and the standard deviation of a data-set?</h3>

The mean of a data-set is given by the <u>sum of all values in the data-set, divided by the number of values</u>.

The standard deviation of a data-set is given by the square root of the <u>sum of the differences squared between each observation and the mean, divided by the number of values</u>.

The mean for this problem is:

M = (17 + 26 + 28 + 9 + 30 + 29 + 6 + 21 + 23)/9 = 21

Hence the standard deviation is:

$S = \sqrt{\frac{(17-21)^2 + (26-21)^2 + (28-21)^2 + \cdots + (21-21)^2 + (23-21)^2}{9}} = 8.22$

More can be learned about the standard deviation of a data-set at brainly.com/question/12180602

#SPJ1

7 0

2 years ago