Answer:
2.
Step-by-step explanation:
The answer is the seocnd one.
Hello! I can help you with this! Do -75/5 to get -15. -15 will be your middle number. So for consecutive integers, -13 + -14 + -15 + -16 + -17 = 75. Those are five consecutive integers that have a sum of 75. The lowest of 5 integers is -17, because it’s the smallest of them all and the furthest to the left of the number line. A line further to the left of the number line means it’s smaller. Therefore, the rest of the five integers is -17.
The slope-intercept is the first option, y=-3x-6
What is the mean and median of 3,1,6,3,6,6,8,2,4,5,5,6,6,3,4,7,9,3,6,10,8,6,5,8,6 I NEED HELP FAST
lapo4ka [179]
Answer:
Median = 6
Mean = 5.44
Step-by-step explanation:
Part 1: Median
So we calculate this problem's median by counting out how many total numbers there are then finding the "middle" number. In this case there are 25 numbers. [(n-1) / 2) +1], Plug 25 in as n --> 24/2 = 12 --> 12 + 1 = 13. =>
So the median of this set would be the 13th number. We can simply count it out and we find that 6 would be the 13th number in this set.
Part 2: Mean
Now we can calculate the mean (average) by adding all the numbers up then dividing by 25 (the amt. of numbers in the whole set). -->
To simply save time, I will just tell you the sum. So correct we if I'm wrong (there are a lot of numbers to add so I might have made a mistake somewere) but I got a total sum of 136 that is not our final answer though because we still need to divide the sum of our numbers by the amt. of numbers in the set (25) =>
136 / 25 = 5.44
And thus, our median is 6, and our mean is 5.44
<em><u>Hope this helps!</u></em>
Answer:
Step-by-step explanation:
16.
(3/5)y = 6
Multiply both sides by 5
3y = 6 times 5
Divide both sides by 3
y = 30/3
y=10
18.
(6/7)c = 18
Multiply both sides by 7
6c = 18 times 7
Divide both sides by6
c = 21
20.
(11/12) = (3/4)h
Multiply both sides by 4
11/3 = 3h
Divide both sides by 3
h = 11/9
22.
m/26 = -1/2
Multiply both sides by 26
m = -13
Hope this helps!
Please mark brainliest if you think I helped! Would really appreciate!