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3 years ago

Braincells = lost can someone fill in the blank

Mathematics

2 answers:

Sergio [31]3 years ago

8 0

Answer:

I believe it’d be 5

Step-by-step explanation:

AH || BC

AH || FG

AH || DE

AB || HG

CD || FE

Masteriza [31]3 years ago

3 0

<h3>Answer: 8 pairs of perpendicular lines</h3>

===============================================

The 8 perpendicular pairs of lines are:

AB and BC
BC and CD
CD and DE
DE and EF
EF and FG
FG and GH
GH and HA
HA and AB

I started with AB and worked counterclockwise around the figure so that I could methodically list each pair of perpendicular lines. Perpendicular lines always form a 90 degree angle. While the square angle markers aren't there, I'm assuming your teacher meant to put them in.

Alternatively, you can count the number of right angles and you'll also get 8 as the answer.

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A school gives awards in five subjects to a class of 30 students but no one is allowed to win more than one award. how many outc

kupik [55]

6 cause u have to multiply 30 and 5

6 0

3 years ago

Suppose a simple random sample of size 50 is selected from a population with σ=10σ=10. Find the value of the standard error of t

bogdanovich [222]

Answer:

a) $\sigma_{\bar x} = 1.414$

b) $\sigma_{\bar x} = 1.414$

c) $\sigma_{\bar x} = 1.414$

d) $\sigma _{\bar x} = 1.343$

Step-by-step explanation:

Given that:

The random sample is of size 50 i.e the population standard deviation =10

Size of the sample n = 50

a) The population size is infinite;

The standard error is determined as:

$\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}$

$\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}$

$\sigma_{\bar x} = 1.414$

b) When the population size N= 50000

n/N = 50/50000 = 0.001 < 0.05

Thus ; the finite population of the standard error is not applicable in this scenario;

Therefore;

The standard error is determined as:

$\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}$

$\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}$

$\sigma_{\bar x} = 1.414$

c) When the population size N= 5000

n/N = 50/5000 = 0.01 < 0.05

Thus ; the finite population of the standard error is not applicable in this scenario;

Therefore;

The standard error is determined as:

$\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}$

$\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}$

$\sigma_{\bar x} = 1.414$

d) When the population size N= 500

n/N = 50/500 = 0.1 > 0.05

So; the finite population of the standard error is applicable in this scenario;

Therefore;

The standard error is determined as:

$\sigma _{\bar x} = \sqrt{\dfrac{N-n}{N-1} }\dfrac{\sigma}{\sqrt{n} } }$

$\sigma _{\bar x} = \sqrt{\dfrac{500-50}{500-1} }\dfrac{10}{\sqrt{50} } }$

$\sigma _{\bar x} = 1.343$

7 0

3 years ago

A cylindrical metal pipe has external diameter of 6cm and internal diameter of 4cm. Calculate the volume of metal in a pipe of l

ArbitrLikvidat [17]

Answer:

volume is 1570 cm³

mass is 12560 g

Step-by-step explanation:

1m = 100 cm

the volume is :

1/4 x $\pi$ x 6² x 100 - 1/4 x $\pi$ x 4² x 100

= 900 $\pi$ - 400 $\pi$ { v = 1/4 $\pi$ d²h }

= 500 $\pi$

= 500 x 3.14

= 1570 cm³

the mass of the pipe is:

1570 x 8 = 12560 grams

5 0

2 years ago

A toy rocket is a composite of a cylindrical body with a cone for a nose. The base of the cylinder and cone are the same size. C

inysia [295]

The volume of the entire rocket given the volumes of the cylindrical body and the cone nose is 117.23 in³.

<h3>What is the volume of the entire rocket?</h3>

The volume of the entire rocket is the sum of the volume of the cylinder and the volume of the cone.

Volume of the cylinder = πr²h

Where:

π = 3.14
r = radius 2
h= height = 12 - 4 = 8 inches

3.14 x 2² x 8 = 100.48 in³

Volume of the cone = 1/3 πr²h

1/3 x 2² x 3.14 x 4 = 16.75 in³

Volume of the rocket = 100.48 + 16.75 = 117.23 in³

To learn more about the volume of a cone, please check: brainly.com/question/13705125

#SPJ1

6 0

2 years ago

Please help! Question above

Gala2k [10]

Answer:

AAS

Step-by-step explanation:

The first A:

∠ABC ≅ ∠DCB

The S:

CB ≅ BC

The second A:

∠A ≅ ∠D

All of them combined to prove ΔABC ≅ ΔDCB through ASA.

8 0

3 years ago