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3 years ago

The function f(x)=−2(0.25)x+1 is shown. Select from the drop-down menus to correctly describe the end behavior of f(x).

Mathematics

1 answer:

Viktor [21]3 years ago

6 0

Answer:

cos 59° = x/16

x = 16 cos 59°

x = 8.24

BC is given 23 mi

Maybe AB is needed

AB = √34² + 23² = 41 (rounded)

BC² = AB² - AC²

BC = √(37² - 12²) = 35

Let the angle is x

cos x = 19/20

x = arccos (19/20)

x = 18.2° (rounded)

See attached

Added point D and segments AD and DC to help with calculation

BC² = BD² + DC² = (AB + AD)² + DC²

Find the length of added red segments

AD = AC cos 65° = 14 cos 65° = 5.9

DC = AC sin 65° = 14 sin 65° = 12.7

Now we can find the value of BC

BC² = (19 + 5.9)² + 12.7²

BC = √781.3

BC = 28.0 yd

All calculations are rounded

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Robert is inspecting a shipment of 22 inch pipes. The length of the pipes may vary by 1%. What is the range of allowable lengths

Slav-nsk [51]

Answer:

The allowable lengths of pipe is from 21.78 inch to 22.22 inch.

Step-by-step explanation:

The length of the each pipe in the shipment = 22 inch

The variation in the length of pipes = 1%

⇒The allowable length of pipe in the inspection = 22 inch ± 1%

Now, 1% of 22 = $\frac{1}{100} \times 22 = 0.22$

So, 22 inch + 1% = 22 inch + 0.22 = 22.22 inch

and 22 inch - 1% = 22 inch - 0.22 = 21.78 inch

⇒ 22 inch ± 1% = 22.22 inch and 21.78 inch

Hence, the allowable lengths of pipe is from 21.78 inch to 22.22 inch.

3 0

3 years ago

Adrian made the cakes shown below for a 3 cakes at the party Adrian will serve each guest 1/8 of a cake what is the greatest num

nikdorinn [45]

Answer:

24 Guests

Step-by-step explanation:

3 x 8 = 24.

4 0

3 years ago

Car leases generally allow only a certain number of miles to be driven. Myung’s lease included a charge of 25 cents per mile for

faust18 [17]

Answer:

36,000

Step-by-step explanation:

if you multiply 12,000 and 3 you get 36,000.

4 0

3 years ago

An environment engineer measures the amount ( by weight) of particulate pollution in air samples ( of a certain volume ) collect

Serggg [28]

Answer:

$k = 1$

$P(x > 3y) = \frac{2}{3}$

Step-by-step explanation:

Given

$f \left(x,y \right) = \left{ \begin{array} { l l } { k , } & { 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x } & { \text 0, { elsewhere. } } \end{array} \right.$

Solving (a):

Find k

To solve for k, we use the definition of joint probability function:

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, = 1$

Where

${ 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x }$

Substitute values for the interval of x and y respectively

So, we have:

$\int\limits^2_{0} \int\limits^{x/2}_{0} {k\ dy\ dx} \, = 1$

Isolate k

$k \int\limits^2_{0} \int\limits^{x/2}_{0} {dy\ dx} \, = 1$

Integrate y, leave x:

$k \int\limits^2_{0} y {dx} \, [0,x/2]= 1$

Substitute 0 and x/2 for y

$k \int\limits^2_{0} (x/2 - 0) {dx} \,= 1$

$k \int\limits^2_{0} \frac{x}{2} {dx} \,= 1$

Integrate x

$k * \frac{x^2}{2*2} [0,2]= 1$

$k * \frac{x^2}{4} [0,2]= 1$

Substitute 0 and 2 for x

$k *[ \frac{2^2}{4} - \frac{0^2}{4} ]= 1$

$k *[ \frac{4}{4} - \frac{0}{4} ]= 1$

$k *[ 1-0 ]= 1$

$k *[ 1]= 1$

$k = 1$

Solving (b): $P(x > 3y)$

We have:

$f(x,y) = k$

Where $k = 1$

$f(x,y) = 1$

To find $P(x > 3y)$ , we use:

$\int\limits^a_b \int\limits^a_b {f(x,y)}$

So, we have:

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {f(x,y)} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {1} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 dxdy$

Integrate x leave y

$P(x > 3y) = \int\limits^2_0 x [0,y/3]dy$

Substitute 0 and y/3 for x

$P(x > 3y) = \int\limits^2_0 [y/3 - 0]dy$

$P(x > 3y) = \int\limits^2_0 y/3\ dy$

Integrate

$P(x > 3y) = \frac{y^2}{2*3} [0,2]$

$P(x > 3y) = \frac{y^2}{6} [0,2]\\$

Substitute 0 and 2 for y

$P(x > 3y) = \frac{2^2}{6} -\frac{0^2}{6}$

$P(x > 3y) = \frac{4}{6} -\frac{0}{6}$

$P(x > 3y) = \frac{4}{6}$

$P(x > 3y) = \frac{2}{3}$

8 0

3 years ago

You and your friend each deposit $50 in separate savings accounts. Your account earns 2% simple annual interest. Your friend’s a

d1i1m1o1n [39]

Answer:

I am will take 20 years to get 20$

My friend will take 10 years to get 20$

Step-by-step explanation:

$Let \: the \: no. \: of \: years : x \\ \\ for \: me \\ x \times (50 \times 2\%) = 20 \\ x \times 1 = 20 \\ x = 20 years\\ for \: my \: friend \\ x \times (50 \times 0.04) = 20 \\ 2x = 20 \\ x = 10 \: years$

I hope this is be good for you and I want this money

7 0

3 years ago