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3 years ago

Which digit(s) make the solution of the equations the whole number? 5x-496=1.34...

Mathematics

1 answer:

umka21 [38]3 years ago

4 0

Answer:

x≈ 100

Step-by-step explanation:

Given the equation

5x-496=1.34...

We are to find the value of x to the nearest whole number

Add 496 to both sides

5x-496+496 = 1.34+496

5x = 497.34

x = 497.34/5

x = 99.468

x ≈ 100

Hence the value of x to nearest whole number is 100

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3 years ago

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Factor 5v^2 - 23v - 10

AfilCa [17]

Answer:

$(5v + 2)(v - 5)$

Step-by-step explanation:

Hello!

The expression is written in the form of $ax^2 + bx + c$

Let's factor by grouping:

$ac = -50$

The sum of the factors of -50 should add up to -23.

-25 and 2 work for this.

Expand and factor:

$5v^2 - 23v - 10$
$5v^2 - 25v + 2v - 10$
$5v(v - 5) +2(v -5 )$
$(5v + 2)(v - 5)$

The factored expression is $(5v + 2)(v - 5)$

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2 years ago

Translate each of the following research questions into appropriate H0 and Ha.

Mandarinka [93]

Answer:

$H_{0}: \mu = 62500\text{ dollars per year}\\H_A: \mu > 62500\text{ dollars per year}$

$H_{0}: \mu = 2.6\text{ hours}\\H_A: \mu \neq 2.6\text{ hours}$

Step-by-step explanation:

We have to build appropriate null and alternate hypothesis for the given scenarios.

a) Population mean, μ = $62,500 per year

The market research wants to find whether the mean household income of mall shoppers is higher than that of the general population.

$H_{0}: \mu = 62500\text{ dollars per year}\\H_A: \mu > 62500\text{ dollars per year}$

We would use one-tail(right) test to perform this hypothesis.

b) Population mean, μ = 2.6 hours

The company want to know the average time to respond to trouble calls is different or not.

$H_{0}: \mu = 2.6\text{ hours}\\H_A: \mu \neq 2.6\text{ hours}$

We would use two-tail test to perform this hypothesis.

7 0

3 years ago

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Triss [41]

Answer:

First option.

Third option.

Fifth option.

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5 0

3 years ago

A long distance runner does a first lap around a track in exactly 50 seconds.As she tires.Each subsequent lap takes 20% longer t

madreJ [45]

Answer:

182 seconds

Step-by-step explanation:

Given:

Time taken for first lap is 50 seconds and each subsequent lap takes 20% longer than previous

Solution:

Time taken for first lap = 50 sec

For second lap

Each subsequent lap takes 20% longer than previous

Previous lap time = 50 sec

second lap = 50 + 20% of 50

second lap $=50+(\frac{20}{100}\times 50)$

second lap $= 50 + 10$

second lap $= 60\ sec$

For third lap

Each subsequent lap takes 20% longer than previous

Previous lap time = 60 sec

Third lap = 60 + 20% of 60

$Third\ lap = 60 + (\frac{20}{100}\times 60)$

$Third\ lap = 60+2\times 6$

$Third\ lap = 60+12$

$Third\ lap = 72\ sec$

Time taken for 3 laps is equal to sum of all three laps time.

$Tiem\ taken\ for\ 3\ lap = 50+60+72$

$Tiem\ taken\ for\ 3\ lap = 182\ sec$

Therefore, it takes 182 seconds (3 min, 2 seconds) to run three laps

6 0

3 years ago