Answer:
(d) -- see attached
Step-by-step explanation:
A graph that shows exponential decay is one that tends toward a horizontal asymptote as x gets large.
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A basic (parent) exponential decay curve is concave upward and tends toward zero as x gets large. The fractional change in any interval is the same as for any other interval of equal size. The curve attached decreases by a factor of 2 when x increases by 1.
Answer:
A. the equality means that the two equations should be equal in a certain x value. Solving the x for these equation gives you the x point where the 2 equations intersect.
B. The x value where the funcionts intersect is x = 1
Step-by-step explanation:
You can solve the x value using natural logarithms.
If you make a table for the two functions you will also see the result:
Value y = 8^x y = 2^(x+2)
-3 0,00195 0,5
-2 0,0156 1
-1 0,125 2
0 1 4
1 8 8
2 64 16
3 512 32
7ft = 84in 84 ÷ 15 = 5.6 pieces he can cut from each board. Since .6 is not a whole piece measuring 15 inches long, he can only cut 5 pieces from each board.
So, 5 x 2 = 10
He would be able to cut 10 pieces measuring 15 inches long.
Hope this helps :)
Answer:

Step-by-step explanation:
Let P denotes principal amount, T denotes time period and R denotes rate of interest.
Amount = 
Amir pits £3035 into a bank account. The account pays 4% compound interest each year.
Put 
Amount = 
Therefore, Amir will have
in the account after 6 years.
Answer:
y-determinant = 2
Step-by-step explanation:
Given the following system of equation:
Let's represent it using a matrix:
![\left[\begin{array}{ccc}1&2\\1&-3\end{array}\right] = \left[\begin{array}{ccc}5\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%5C%5C1%26-3%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
The y‐numerator determinant is formed by taking the constant terms from the system and placing them in the y‐coefficient positions and retaining the x‐coefficients. Then:
![\left[\begin{array}{ccc}1&5\\1&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%265%5C%5C1%267%5Cend%7Barray%7D%5Cright%5D%20)
y-determinant = (1)(7) - (5)(1) = 2.
Therefore, the y-determinant = 2