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3 years ago

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A scientist measure change in the temperature of chemical solution at the start of the experiment , the solutions is at temperat

ure of -14.96C. The temperature decreases 2.9C each hour

1 answer:

zhannawk [14.2K]3 years ago

4 0

Answer:

The temperature of the chemical solution after t hours is $-14.96-2.9t\;^{\circ}C$

Step-by-step explanation:

Given that the initial temperature of the chemical solution, $T_0= -14.96^{\circ}C$ .

The rate of decreasing temperature, $R = 2.9^{\circ}C/ hour$

So, after t hours, the temperature of the chemical solution will decrease by $Rt=2.9t^{\circ}C$ .

So, the temperature of the chemical solution after t hours,

$T=T_0-Rt \\\\\Rightarrow T = -14.96-2.9t\;^{\circ}C$

Hence, the temperature of the chemical solution after t hours is $-14.96-2.9t^{\circ}C$ .

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Read 2 more answers

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rusak2 [61]

$\hbox{Domain:}\\
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$
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(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\
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$
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There's one more condition I forgot about
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3 0

3 years ago