I need help I don’t understand it

Determine the length of GH. Round to the nearest tenth. 3.9 cm G 52 642 H

sesenic [268]

Answer:

|GH| = 5,7 cm

Step-by-step explanation:

To know |GH|, you first need to find the length of |GD|.

We can calculate |GD| by;

cosG = |GC| / |GD|

<=> |GD| = |GC| / cosG

=> |GD| = 3,9 cm/ 0,62 = 6,33 cm

We now can easily calculate |GH| with the sinus of angle D;

sinD = |GH| / |GD|

<=> |GH| = sinD.|GD|

=> |GH| = 0,899.6,33 cm = 5,694 cm => 5,7 cm

I hope i did not make a mistake ...

5 0

3 years ago

The 10th term of an a.p is -27 and the 5th term is -12 .find the first term?

horsena [70]

Step-by-step explanation:

$a_{10} = - 27... (Given) \\\\\therefore a + 9d = - 27...... (1)\\\\a_{5} = - 12... (Given) \\\\\therefore a + 4d = - 12.......(2)\\\\$

Subtracting equation (2) from equation (1)

$a + 9d-( a + 4d )= - 27-(-12)\\\\\therefore a +9d - a-4d = - 27+12\\\\\therefore 5d = - 15\\\\\therefore d = \frac {- 15}{5}\\\\\huge \orange {\boxed {\therefore d = -3}} \\\\$

Substituting d = - 3 in equation (1), we find:

$a + 9\times (-3)= - 27\\\\\therefore a - 27 = - 27\\\\\therefore a = 27- 27\\\\\huge \red {\boxed {\therefore a = 0}}\\\\$

Hence, first term is zero.

3 0

3 years ago

NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)

olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level PA (men) PA (Women)

Sedentary 1.00 1.00

Low 1.11 1.12

Active 1.25 1.27

Very Active 1.48 1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

$= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962$

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0

3 years ago

Mr. Wallace gave a test to his math classes. He created a histogram that showed the frequency of As, Bs, and Cs. He labeled the

Gennadij [26K]

Answer:

D

Step-by-step explanation:

I got it right on Khan Academy

3 0

3 years ago

Find the missing length of the right triangle

LiRa [457]

Is their suppose to be a picture ?

8 0

3 years ago