Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45
Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239
Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102
Solving for y,
y = -2(102) + 239
y = 35
Solving for z,
z = 102 - 45
z = 57
So if all same you just simplify The top : 2x+1+x+4 2x+x+1+4
3x+5 The bottom all same just use one .x-3 3x+5/x-3
41.5 times 8.4 is the equation your in high school so you should know the rest
P(A)= 4+5+6= 15/2= 75%
P(B)= 6+4=10 5/10= 50%
P(C)= 5+4=9 6/9= 66.6%