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kumpel [21]
3 years ago
15

Please solve thank you very much!!

Mathematics
2 answers:
cricket20 [7]3 years ago
5 0

Answer:

Its C. Subtract 9 on both sides

Step-by-step explanation:

jeyben [28]3 years ago
3 0
Subtract 9 by both sides
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16. How much money will I need to have at retirement so I can withdraw $60,000 a year for 20 years from an account earning 8% co
Lady_Fox [76]

Answer:

  • starting balance: $636,215.95
  • total withdrawals: $1,200,000
  • interest withdrawn: $563,784.05

Step-by-step explanation:

a) If we assume the annual withdrawals are at the beginning of the year, we can use the formula for an annuity due to compute the necessary savings.

The principal P that must be invested at rate r for n annual withdrawals of amount A is ...

  P = A(1+r)(1 -(1 +r)^-n)/r

  P = $60,000(1.08)(1 -1.08^-20)/0.08 = $636,215.95

__

b) 20 withdrawals of $60,000 each total ...

  20×$60,000 = $1,200,000

__

c) The excess over the amount deposited is interest:

  $1,200,000 -636,215.95 = $563,784.05

4 0
3 years ago
4/2n+5/3c=1<br> Solve for c.<br><br> -Multiply both sides by (blank) to clear fractions.
blsea [12.9K]

Answer:

We conclude that:

c=-\frac{5n}{3\left(-n+2\right)};\quad \:n\ne \:2

Step-by-step explanation:

Given the expression

\frac{4}{2n}+\frac{5}{3c}=1

<u>Let us solve for 'c'</u>

\frac{4}{2n}+\frac{5}{3c}=1

Least Common Multiplier of 2n, 3c:   6nc

Now multiply both sides by LCM = 6nc

\frac{4}{2n}\cdot \:6nc+\frac{5}{3c}\cdot \:6nc=1\cdot \:6nc

Simplify

12c+10n=6nc

Subtract 10n from both sides

12c+10n-10n=6nc-10n

Simplify

12c=6nc-10n

Subtract 6nc from both sides

12c-6nc=6nc-10n-6nc

Simplify

12c-6nc=-10n

Factor 12c - 6nc = 6c(2-n)

6c\left(2-n\right)=-10n

Divide both sides by 6(2-n);  n≠2

\frac{6c\left(2-n\right)}{6\left(2-n\right)}=\frac{-10n}{6\left(2-n\right)};\quad \:n\ne \:2

simplify

c=-\frac{5n}{3\left(-n+2\right)};\quad \:n\ne \:2

Therefore, we conclude that:

c=-\frac{5n}{3\left(-n+2\right)};\quad \:n\ne \:2

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